Ask question

Ask question

All categories

2 years ago

6

A plant nusery is growing a tree that is 3 ft. tall and grows at an average rate of 1 ft. per year. Another tree at the nursery

is 4 ft. tall and grows at an average rate of 0.5 feet per year. After how many years will the trees be the same height? show work.
Need help ASAP due tmr!!

1 answer:

nignag [31]2 years ago

7 0

The tree will both be 5 feet after 2 years.

y=x + 3

y = 1/2x + 4

You might be interested in

I need someone to help me please

zhuklara [117]

<span>the answer is =<span><span>‌<span>7/24</span></span><span>‌</span></span></span>

4 0

3 years ago

Read 2 more answers

the world's largest Apple had a mass of 1849 grams sue said the mass was greater than 2 kilogram does she stament make sense plz

Monica [59]

No, 2 kilograms are 2000 grams.

6 0

3 years ago

Shelley’s pet food store sold one customer 5 peanut butter biscuits for $3. She sold another customer 7 beef treats for $4.20.

tatuchka [14]

Answer:

I think that is the answer to this math work 5 × 3= $15 7 × $4.20=$29.40 All together it will be $44.40

3 0

3 years ago

Read 2 more answers

There is strong believe that language skills of Political science students are greater than students who study Finance. Research

BaLLatris [955]

Answer:

a

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis $H_a : \mu_1 > \mu_2$

b

$p-value = 0.232$

c

The decision rule is

Fail to reject the null hypothesis

Step-by-step explanation:

From the question we are told that

The value given is

S/N

1 7 5

2 4 3

3 8 7

4 8 8

5 7 9

6 7 5

7 6 5

Generally the sample mean for the first sample is mathematically represented as

$\= x _1 = \frac{\sum x_i }{n}$

=> $\= x _1 = \frac{7 +4 + \cdots + 6}{7}$

=> $\= x _1 = 6.714$

Generally the sample mean for the second sample is mathematically represented as

$\= x _2 = \frac{\sum x_i }{n}$

=> $\= x _2 = \frac{5 + 3+ \cdots + 5}{7}$

=> $\= x _2 = 6$

Generally the sample standard deviation for the first sample is mathematically represented as

$s_1 = \sqrt{\frac{\sum (x_i - \= x_1)^2 }{n-1 } }$

=> $s_1 = \sqrt{\frac{ (7 - 6.714 )^2 +(4 - 6.714 )^2 + \cdots + (6 - 6.714 )^2 }{7-1 } }$

=> $s_1 = 1.905$

Generally the sample standard deviation for the second sample is mathematically represented as

$s_2 = \sqrt{\frac{\sum (x_i - \= x_2)^2 }{n-1 } }$

=> $s_2 = \sqrt{\frac{ (5 - 6.714 )^2 +(3 - 6.714 )^2 + \cdots + (5 - 6.714 )^2 }{7-1 } }$

=> $s_1 = 4.33$

Generally the pooled standard deviation is

$s = \sqrt{\frac{(n_1 - 1 )s_1^2 + (n_2 - 1 )s_2^2}{n_1 + n_2 -2 } }$

=> $s = \sqrt{\frac{(7 - 1 )1.905^2 + (7 - 1 )4.333^2}{7 + 7 -2 } }$

=> $s = 1.766$

The null hypothesis is $H_o : \mu_1 = \mu_2$

The alternative hypothesis $H_a : \mu_1 > \mu_2$

Generally the test statistics is mathematically represented as

$t = \frac{\= x _1 - \= x_2 }{s * \sqrt{\frac{1}{n_1} + \frac{1}{n_2}} }$

=> $t = \frac{6.714 - 6 }{1.766 * \sqrt{\frac{1}{7} + \frac{1}{7}} }$

=> $t = 0.757$

Generally the degree of freedom is mathematically represented as

$df = n_1 + n_2 - 2$

=> $df = 7 + 7 - 2$

=> $df = 12$

From the t distribution table the probability of $t = 0.757$ at a degree of freedom of $df = 12$ is

$t_{ 0.757 , 12} = 0.232$

Generally the p-value is

$p-value = t_{ 0.757 , 12} = 0.232$

From the values obtained we see that $p-value > \alpha$ hence

The decision rule is

Fail to reject the null hypothesis

8 0

3 years ago

Anyone know how to do this?!!

iren2701 [21]

Answer:

slope is -1/4

Step-by-step explanation:

$\frac{-4}{12}$ = $\frac{-1}{4}$

$\frac{-2}{8}$ = $\frac{-1}{4}$

and so on...

formula: $\frac{x}{y}$

hope this helps!!!

6 0

2 years ago