We are asked to determine the correlation factor "r" of the given table. To do that we will first label the column for "Quality" as "x" and the column for "Easiness" as "y". Like this:
Now, we create another column with the product of "x" and "y". Like this:
Now, we will add another column with the squares of the values of "x". Like this:
Now, we add another column with the squares of the values of "y":
Now, we sum the values on each of the columns:
Now, to get the correlation factor we use the following formula:

Where:

Now we substitute the values, we get:

Solving the operations:

Therefore, the correlation factor is 0.858. If the correlation factor approaches the values of +1, this means that there is a strong linear correlation between the variables "x" and "y" and this correlation tends to be with a positive slope.
A.
B and C are wrong because x is more than or equal to 3.
D is wrong because y is the weight of oranges and cannot be negative.
The answer is 5 I’m not sure if this is correct
Answer:
z is less than 3/4
Step-by-step explanation:
Since 90 degree is 1/4 of a circle, the area will be 1/4 th area of the full circle.
The radius is given by, r = 8 ft, therefore, the area of the full circle is,

Therefore, the area of the sector is,
