Answer:
<u>C) 4</u>
Explanation:
<u>The reaction</u> :
- C (s) + 2H₂ (g) ⇒ CH₄ (g)
        12g      4g             16g
Hence, based on this we can say that : <u>2 moles of hydrogen gas are needed to produce 16g of methane.</u>
<u />
<u>For 32g of methane</u>
- Number of moles of H₂ = 32/16 × 2
- Number of moles of H₂ = <u>4</u>
 
        
                    
             
        
        
        
Answer:
the first answer is correct don't forget you can use quizzlet app to
 
        
             
        
        
        
Answer:
Mass of NH₃ produced = 34 g
Explanation:
Given data:
Mass of nitrogen = 28 g
Mass of Hydrogen = 12 g
Mass of NH₃ produced = ?
Solution:
Chemical equation:
N₂ +  3H₂    →   2NH₃
Moles of nitrogen:
Number of moles = mass/molar mass
Number of moles = 28 g/ 28 g/mol
Number of moles = 1 mol
Moles of hydrogen:
Number of moles = mass/molar mass
Number of moles = 12 g/ 2 g/mol
Number of moles = 6 mol
Now we will compare the moles of hydrogen and nitrogen with ammonia.
                             H₂              :               NH₃
                             3                :                2
                             6                :             2/3×6 = 4 mol
                            N₂              :                NH₃
                             1                :                 2
Number of moles of ammonia produced by nitrogen are less thus it will act as limiting reactant.
Mass of ammonia produced:
Mass = number of moles × molar mass
Mass =  2 mol  ×  17 g/mol
Mass = 34 g
                      
 
        
                    
             
        
        
        
Water is a compound that is made up of oxygen and hydrogen atoms, therefore the smallest particle of water is water molecule. The smallest particle representing water is written as H2O. H2O is the smallest unit to which water can be split while still retaining the properties of water.