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3 years ago

Solve the equations -7x - 93 = 150 + 2x

Mathematics

2 answers:

mario62 [17]3 years ago

5 0

Answer:

X=-27

Step-by-step explanation:

So -9x=150+93

Or -9x=243

So x=-27

VARVARA [1.3K]3 years ago

4 0

Add 7 to both sides

-93 = 150 + 2x + 7x

Simplify 150 + 2x + 7x to 150 + 9x

-93 = 150 + 9x

Subtract 150 from both sides

-93 - 150 = 9x

Simplify -93 - 150 to -243

-243 = 9x

Divide both sides by 9

-243/9 = x

Simplify 243/9 to 27

-27 = x

Switch sides

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Simplify this expression. 6^7 ÷ 6^5 A. 30 B. 35 C. 36 D. 42

bulgar [2K]

Answer:

C 36

Step-by-step explanation:

When we have to exponents to the same base, and we are dividing them, we can subtract the exponents

a^b ÷ a^c = a^ (b-c)

6^7 ÷ 6^5 = 6^(7-5)

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6 0

3 years ago

Read 2 more answers

The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a

Anettt [7]

Answer:

1) The size of the colony after 4 days is 6553 mosquitoes

2) After $t = 4.9\ days$

Step-by-step explanation:

To answer this question you must use the growth formula

$N = N_0e ^ {kt}$

Where

$N_0$ is the initial population of mosquitoes = 1000

t is the time in days

k is the growth rate

N is the population according to the number of days

We know that when t = 1 and $N_0=1000$ then N = 1600

Then we use these values to find k.

$1600 = 1000e ^{k(1)}\\\\\frac{1600}{1000} = e ^ k\\\\ln(\frac{1600}{1000}) = k\\\\k = 0.47$

Now that we know k we can find the size of the colony after 4 days.

$N = 1000e ^ {0.47(4)}\\\\N = 6553\ mosquitoes$

To know how long it should take for the population to reach 10,000 mosquitoes we must do N = 10000 and solve for t.

$10000 = 1000e ^ {0.47t}\\\\10 = e ^ {0.47t}\\\\ln(10) = 0.47t\\\\t = \frac{ln(10)}{0.47}\\\\t = 4.9\ days$

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Tpy6a [65]

Answer:

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Step-by-step explanation:

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