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Furkat [3]
3 years ago
7

A farmer is tilling a rectangular field that is 65 meters long and 72 meters wide. What is the distance between opposite corners

of the farmer's field

Mathematics
1 answer:
ss7ja [257]3 years ago
3 0

Answer:

97m

Step-by-step explanation:

From the image below we solve using pythagoras's theorem

x^2 = 72^2 + 65^2

x^2 = 5184 + 4225

x^2 = 9408

x = 97 m.

Further explanation is shown 8n the image.

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Which would most likely be graphed using a continuous graph? Check all that apply. (Medal for correct answer.
zlopas [31]
We need an image to be able to answer this question

7 0
2 years ago
If a 24-kg mass stretches a spring 15 cm, what mass will stretch the spring 10 cm
natulia [17]

Answer:

<h2>16kg</h2>

Step-by-step explanation:

 This problem is borers on elasticity of materials.

according to Hooke's law,<em> "provided the elastic limit of an elastic material is not exceeded the the extension e is directly proportional to the applied force."</em>

F= ke

where F is the applied force in N

          k is the spring constant N/m

          e is the extension in meters

Given data

mass m= 24kg

extensnion=15cm in meters= \frac{15}{100}= 0.15m

we can solve for the spring constant k

we also know that the force F = mg

assuming g=9.81m/s^{2}

therefore

24*9.81=k*0.15\\235.44=k*0.15\\k=\frac{235.44}{0.15} \\k=1569.6N/m\\

We can use this value of k to solve for the mass that will cause an extension of  10cm= 0.1m

x*9.81=1569.6*0.1\\\\x= \frac{156.96}{9.81} \\\x= 16kg

5 0
3 years ago
Haley is stacking bricks to make a garden wall there are 18 bricks in all if each brick weighs 5.3 pounds how much do the bricks
Sophie [7]
The answer is 42.4 because I times it: 5.3 * 18 = 95.39
8 0
3 years ago
Read 2 more answers
The chart shows the high temperature each day in Fairbanks, Alaska during the month of February 2009. What was the median high t
Montano1993 [528]

Answer:

Depends on the data

Step-by-step explanation:

You need to arrange all of the data from the chart in numerical order.

Then figure out which number/numbers are in the middle of the data line.

If it was just one number that is the median. If two numbers were in the middle add them together then divide by two, that is your median.  

7 0
3 years ago
Read 2 more answers
How do you do these two questions?
nignag [31]

Step-by-step explanation:

(a) ∫₋ₒₒ°° f(x) dx

We can split this into three integrals:

= ∫₋ₒₒ⁻¹ f(x) dx + ∫₋₁¹ f(x) dx + ∫₁°° f(x) dx

Since the function is even (symmetrical about the y-axis), we can further simplify this as:

= ∫₋₁¹ f(x) dx + 2 ∫₁°° f(x) dx

The first integral is finite, so it converges.

For the second integral, we can use comparison test.

g(x) = e^(-½ x) is greater than f(x) = e^(-½ x²) for all x greater than 1.

We can show that g(x) converges:

∫₁°° e^(-½ x) dx = -2 e^(-½ x) |₁°° = -2 e^(-∞) − -2 e^(-½) = 0 + 2e^(-½).

Therefore, the smaller function f(x) also converges.

(b) The width of the intervals is:

Δx = (3 − -3) / 6 = 1

Evaluating the function at the beginning and end of each interval:

f(-3) = e^(-9/2)

f(-2) = e^(-2)

f(-1) = e^(-1/2)

f(0) = 1

f(1) = e^(-1/2)

f(2) = e^(-2)

f(3) = e^(-9/2)

Apply Simpson's rule:

S = Δx/3 [f(-3) + 4f(-2) + 2f(-1) + 4f(0) + 2f(1) + 4f(2) + f(3)]

S ≈ 2.5103

5 0
2 years ago
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