HURRY PLEASE!! How would you graph this on a slope?

ludmilkaskok [199]

Answer:

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Step-by-step explanation:

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7 0

2 years ago

Please help!

dalvyx [7]

Answer:

the answer is y=1/3x+20

Step-by-step explanation:

because he is going 3 times faster and you are adding on the 20 minutes that he is late

6 0

2 years ago

Read 2 more answers

A conical water tank with vertex down has a radius of 13 feet at the top and is 21 feet high. If water flows into the tank at a

VLD [36.1K]

Answer:

$\frac{dh}{dt}\approx0.08622\text{ ft/min}$

Step-by-step explanation:

We know that the conical water tank has a radius of 13 feet and is 21 feet high.

We also know that water is flowing into the tank at a rate of 30ft³/min. In other words, our derivative of the volume with respect to time t is:

$\frac{dV}{dt}=\frac{30\text{ ft}^3}{\text{min}}$

We want to find how fast the depth of the water is increasing when the water is 17 feet deep. So, we want to find dh/dt.

First, remember that the volume for a cone is given by the formula:

$V=\frac{1}{3}\pi r^2h$

We want to find dh/dt. So, let's take the derivative of both sides with respect to the time t. However, first, let's put the equation in terms of h.

We can see that we have two similar triangles. So, we can write the following proportion:

$\frac{r}{h}=\frac{13}{21}$

Multiply both sides by h:

$r=\frac{13}{21}h$

So, let's substitute this in r:

$V=\frac{1}{3}\pi (\frac{13}{21}h)^2h$

Square:

$V=\frac{1}{3}\pi (\frac{169}{441}h^2)h$

Simplify:

$V=\frac{169}{1323}\pi h^3$

Now, let's take the derivative of both sides with respect to t:

$\frac{d}{dt}[V]=\frac{d}{dt}[\frac{169}{1323}\pi h^3}]$

Simplify:

$\frac{dV}{dt}=\frac{169}{1323}\pi \frac{d}{dt}[h^3}]$

Differentiate implicitly. This yields:

$\frac{dV}{dt}=\frac{169}{1323}\pi (3h^2)\frac{dh}{dt}$

We want to find dh/dt when the water is 17 feet deep. So, let's substitute 17 for h. Also, let's substitute 30 for dV/dt. This yields:

$30=\frac{169}{1323}\pi (3(17)^2)\frac{dh}{dt}$

Evaluate:

$30=\frac{146523}{1323}\pi( \frac{dh}{dt})$

Multiply both sides by 1323:

$39690=146523\pi\frac{dh}{dt}$

Solve for dh/dt:

$\frac{dh}{dt}=\frac{39690}{146523}\pi$

Use a calculator. So:

$\frac{dh}{dt}\approx0.08622\text{ ft/min}$

The water is rising at a rate of approximately 0.086 feet per minute.

And we're done!

Edit: Forgot the picture :)

3 0

3 years ago

A truck driver drove 13 hours and earned $520. What is the hourly rate?

Lorico [155]

Answer:

$40

Step-by-step explanation:

520/13=40

6 0

2 years ago

Read 2 more answers

A rectangle in the xy-coordinate plane is formed by the points (1,−4), (1,6), (3,−4), and (3,6). What is the perimeter of this r

Airida [17]

Answer:

Perimeter of the rectangle= $20+2\sqrt{104}$

Step-by-step explanation:

The perimeter of the rectangle with the given coordinates is the sum of its all four sides:

Let the points be A(1,-4), B(1,6), C(3,-4) and D(3,6)

Finding the sides of the rectangle using the Distance formula:

AB=

$\sqrt{(1-1)^2+(6-(-4))^2} \\\\=\sqrt{0+10^2} \\\\=\sqrt{100}\\\\ =10$

BC

$=\sqrt{(3-1)^2+(-4-6)^2} \\\\=\sqrt{2^2+(-10)^2}\\\\ =\sqrt{4+100} \\\\=\sqrt{104}$

CD=

$\sqrt{(3-3)^2+(6-(-4))^2} \\\\=\sqrt{0+10^2} \\\\=\sqrt{100} \\\\=10$

AD=

$\sqrt{(3-1)^2+(6-(-4))^2} \\\\=\sqrt{2^2+10^2} \\\\=\sqrt{4+100}\\\\ =\sqrt{104}$

Perimeter of the rectangle=AB+BC+CD+AD

= $10+\sqrt{104}+ 10+\sqrt{104}$

Perimeter of the rectangle= $20+2\sqrt{104}$

7 0

3 years ago

HURRY PLEASE!!How would you graph this on a slope?​

HURRY PLEASE!!How would you graph this on a slope?