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3 years ago

The proper pruning tool to use when branches are smaller than 1" in thickness, but larger than 3/8" in thickness is:

1 answer:

6 0

The answer that fits the blank is LOPPER. The lopper is actually a tool that is used for cutting, particularly in the pruning of trees. It is a scissor type tool that is applicable for cutting smaller branches and twigs, and has a long handle.

You might be interested in

Two values less than seven hundred three and forty seven thousandths

jenyasd209 [6]

Answer:

47701

Step-by-step explanation:

(703+47000)-2=

47703-2=

47701

7 0

3 years ago

A sphere and a cylinder have the same radius and height. The volume of the cylinder is 21 meters cubed. A sphere with height h a

Elodia [21]

We have been given that a sphere and a cylinder have the same radius and height. The volume of the cylinder is 21 meters cubed. We are asked to find the volume of the sphere.

We know that height of sphere is equal to its radius. This means that $r=h$ .

$\text{Volume of sphere}=\frac{4}{3}\pi r^3$

$\text{Volume of cylinder}=\pi r^2 h$

Using $r=h$ , we will get:

$\text{Volume of cylinder}=\pi r^2\cdot r$

$\text{Volume of cylinder}=\pi r^3$

Upon comparing volume of sphere and volume of cylinder, we can see that volume of sphere is $\frac{4}{3}$ times volume of cylinder.

$\pi r^3=21$

$\frac{4}{3}\pi r^3=\frac{4}{3}\cdot 21$

$\frac{4}{3}\pi r^3=4\cdot 7$

$\frac{4}{3}\pi r^3=28$

Therefore, the volume of the sphere would be 28 cubic meters.

4 0

3 years ago

Read 2 more answers

x2 + y2 − 4x + 12y − 20 = 0 (x − 6)2 + (y − 4)2 = 56 x2 + y2 + 6x − 8y − 10 = 0 (x − 2)2 + (y + 6)2 = 60 3x2 + 3y2 + 12x + 18y −

snow_tiger [21]

For this case, what we must do is fill squares in all the expressions until we find the correct result.
We have then:

x2 + y2 − 4x + 12y − 20 = 0 x2 + y2 − 4x + 12y = 20
x2 − 4x + y2 + 12y = 20
x2 − 4x + (12/2)^2 + y2 + 12y + (-4/2)^2 = 20 + (12/2)^2 + (-4/2)^2
x2 − 4x + (6)^2 + y2 + 12y + (-2)^2 = 20 + (6)^2 + (-2)^2
x2 − 4x + 36 + y2 + 12y + 4 = 20 + 36 + 4
(x − 2)2 + (y + 6)2 = 60

3x2 + 3y2 + 12x + 18y − 15 = 0
x2 + y2 + 4x + 6y − 5 = 0
x2 + y2 + 4x + 6y = 5
x2 + 4x + (4/2)^2 + y2 + 6y + (6/2)^2 = 5 + (4/2)^2 + (6/2)^2
x2 + 4x + (2)^2 + y2 + 6y + (3)^2 = 5 + (2)^2 + (3)^2
x2 + 4x + 4 + y2 + 6y + 9 = 5 + 4 + 9
(x + 2)2 + (y + 3)2 = 18

2x2 + 2y2 − 24x − 16y − 8 = 0
x2 + y2 − 12x − 8y − 4 = 0
x2 + y2 − 12x − 8y = 4
x2 − 12x + (-12/2)^2 + y2 − 8y + (-8/2)^2 = 4 + (-12/2)^2 + (-8/2)^2
x2 − 12x + (-6)^2 + y2 − 8y + (-4)^2 = 4 + (-6)^2 + (-4)^2
x2 − 12x + 36 + y2 − 8y + 16 = 4 + 36 + 16
(x − 6)2 + (y − 4)2 = 56

x2 + y2 + 2x − 12y − 9 = 0
x2 + y2 + 2x - 12y = 9
x2 + 2x + y2 - 12y = 9
x2 + 2x + (2/2)^2 + y2 - 12y + (-12/2)^2 = 9 + (2/2)^2 + (-12/2)^2
x2 + 2x + (1)^2 + y2 - 12y + (-6)^2 = 9 + (1)^2 + (-6)^2
x2 + 2x + 1 + y2 - 12y + 36 = 9 + 1 + 36
(x + 1)2 + (y − 6)2 = 46

7 0

3 years ago

One container is filled with a mixture that is 30%acid a second container is filled with a mixture that is 50%acid the second co

julsineya [31]

Answer:

The amount of acid in third container is =42%

Step-by-step explanation:

Given , one container is filled with a mixture that is 30% acid a second container filled with a mixture that is 50% acid and the second container 50% larger than the first .

Let, the volume of first container is = x

Then , the volume of second container = (x+ x of 50%)

= x + 0.5 x

= 1.5 x

Therefore the amount of acid in first container $=x \times \frac{30}{100}$ = 0.3 x