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igor_vitrenko [27]
2 years ago
9

A straight road crosses two parallel railway tracks. The angle between the road and the

Mathematics
1 answer:
Mumz [18]2 years ago
7 0
<h3>Answer:  95 degrees</h3>

=======================================================

Explanation:

I recommend drawing it out to see what's going on. See the drawing below.

In the diagram, both angles are in the northeast corner of their four-corner configurations. They are both congruent corresponding angles. So that's why the second angle is also 95 degrees.

Side note: we could replace "northeast" with any of the other directions on the compass (such as southwest). All that matters is that they are in the same configuration.

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The solutions to a certain quadratic equation are x = -4 and x = 3. Write the equation in standard form below.
saw5 [17]

Answer:

x^2 + x -12

Step-by-step explanation:

If the solutions are x=-4 and x=3, then it must have factors (x+4)(x-3). Assuming there is no GCF or leading coefficient other than 1, multiply with FOIL to find the standard form.

(x+4)(x-3)\\x^2 + 4x -3x -12\\x^2 + x -12

7 0
3 years ago
Read 2 more answers
Determine the number of real solutions for each of the given equations. Equation Number of Solutions y = -3x2 + x + 12 y = 2x2 -
rosijanka [135]

Answer:

Step-by-step explanation:

Our equations are

y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\

Let us understand the term Discriminant of a quadratic equation and its properties

Discriminant is denoted by  D and its formula is

D=b^2-4ac\\

Where

a= the coefficient of the x^{2}

b= the coefficient of x

c = constant term

Properties of D: If D

i) D=0 , One real root

ii) D>0 , Two real roots

iii) D<0 , no real root

Hence in the given quadratic equations , we will find the values of D Discriminant  and evaluate our answer accordingly .

Let us start with

y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\

Hence we have two real roots for this equation.

y = 2x^2 - 6x + 5\\

y = 2x^2 - 6x + 5\\a=2,b=-6,c=5\\D=(-6)^2-4*2*5\\D=36-40\\D=-4\\D

Hence we do not have any real root for this quadratic

y = x^2 + 7x - 11\\a=1,b=7,-11\\D=7^2-4*1*(-11)\\D=49+44\\D=93\\

Hence D>0 and thus we have two real roots for this equation.

y = -x^2 - 8x - 16\\a=-1,b=-8,c=-16\\D=(-8)^2-4*(-1)*(-16)\\D=64-64\\D=0\\

Hence we have one real root to this quadratic equation.

7 0
3 years ago
Write the subtraction problem below as an equation
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What is 7 to the fourth power
Snezhnost [94]
7×7×7×7 = 7^4 = 2,401
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3 years ago
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$893.996 rounded to the nearest cent
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Answer:

$893.666 rounded to the nearest cent  is $894.00

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