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dimulka [17.4K]
3 years ago
5

10,000+50+5 in standard form

Mathematics
1 answer:
Katarina [22]3 years ago
7 0
10,055
this is the right answer ^
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Juan and Dylan are selling bottled water. Juan sold 4 bottles for every 6 that Dylan sold. Dylan sold 16 more bottles than Juan.
Dimas [21]

Answer:

Dylan sold 48 bottles

Juan sold 32 bottles

Step-by-step explanation:

The ratio of bottles sold is;

J:D = 4:6

Dylan sold 16 more than Juan

That means d = j + 16

so;

j/j + 16 = 4/6

6j = 4(j + 16)

6j = 4j + 64

6j - 4j = 64

2j = 64

j = 64/2

j = 32

d = j + 16

d = 32 + 16

d = 48

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3 years ago
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The answer is 6 x 3 x 3 = 54.
I found this by finding the surface area with 9 x 6 and then seeing that 6 x 3 x 3 gives the same answer knew that one was correct, but I'm sure there's an easier way, good luck.
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3 years ago
Is square root 1 minus sine squared theta = cos Θ true? If so, in which quadrants does angle Θ terminate?
Cloud [144]

Answer:

True; quadrants I & IV

Step-by-step explanation:

We know the relation between sine and cosine function which is given by

\sin^2 \theta +\cos^2 \theta = 1

Let us solve this equation for cosine function.

\cos^2 \theta = 1-\sin^2 \theta

Take square root both sides. When ever we take square root we need to write the solution in plus minus form

\sqrt{\cos^2 \theta}=\pm\sqrt{1-\sin^2 \theta}

\cos \theta=\pm\sqrt{1-\sin^2 \theta}

\cos \theta=-\sqrt{1-\sin^2 \theta}, \sqrt{1-\sin^2 \theta}

If Θ is in quadrants I and IV then the value will be positive and if Θ is in II and III quadrant then the value is negative.

Hence, if Θ is in quadrants I & IV, then we have

\cos \theta=\sqrt{1-\sin^2 \theta}

Thus, the correct option is: True; quadrants I & IV


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4 years ago
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