Answer:
-2(2x+4)
Step-by-step explanation:
Answer and Step-by-step explanation:
The signs didn't really "swap". Instead, the whole function was divided by -1, or we could say the function was divided by -3. That would turn:
-18x² - 15x + 3 = 0
into
(-18 / -3)x² - (15 / -3)x + (3 / -3) = 0
6x² + 5x - 1 = 0
And that gives the "swapped signs".
Answer:
A.The probability that exactly six of Nate's dates are women who prefer surgeons is 0.183.
B. The probability that at least 10 of Nate's dates are women who prefer surgeons is 0.0713.
C. The expected value of X is 6.75, and the standard deviation of X is 2.17.
Step-by-step explanation:
The appropiate distribution to us in this model is the binomial distribution, as there is a sample size of n=25 "trials" with probability p=0.25 of success.
With these parameters, the probability that exactly k dates are women who prefer surgeons can be calculated as:

A. P(x=6)

B. P(x≥10)




C. The expected value (mean) and standard deviation of this binomial distribution can be calculated as:

Answer:
the answer is 7.2 10³
Step-by-step explanation:
7.2 10³
Answer:
If Elizabeth randomly chooses her ride in the morning and in the evening, 2/3 is the probability that she'll use a cab exactly one time