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natka813 [3]
3 years ago
15

If 6+7=41 then what is 7+8=

Mathematics
1 answer:
Tamiku [17]3 years ago
5 0

Answer:

55 maybe?

Step-by-step explanation:

6*7=42

42-1=41

Then

7*8=56

56-1=55

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Using the figure below find what m<_7 equals. (show work if possible)
miss Akunina [59]

Answer:

68

Step-by-step explanation:

m7 + m8 = Straight line = 180

So, m7 = 180 - 112 = 68

8 0
3 years ago
For questions 2 z 3. simplify each polynomial <br>2. 3x²+6-2x+5x-4x²+9<br>3. 2x²+6x-7x+8-3x²+1​
Mars2501 [29]

Answer:

2. -x^{2} +3x+15

3. -x^{2} -x+9

Step-by-step explanation:

We add like terms together to simplify

2.  3x²-4x²= -x²     -2x+5x= 3x  6+9= 15  all equal to -x²+3x+15

3.  2x²-3x²= -x²      6x-7x= -x    8+1=9      all equal to -x²-x+9

7 0
2 years ago
Triangle ABC is shown below.
Andrew [12]

Answer:

C.) 14

Step-by-step explanation:

Look at the triangle: angles b and c have the same arch, so they are congruent.

In a triangle, if two angles are congruent, then the triangle is isosceles, having two equal sides.

The sides opposite the congruent angles are congruent:

∠B → opposite side → AC

∠C → opposite side → AB

The sides AB and AC are equal. Make an equation:

AB=AC\\\\2x=3x-7

Simplify the equation, solving for x. Add 7 to both sides:

2x+7=3x-7+7\\\\2x+7=3x

Subtract 2x from both sides:

2x-2x+7=3x-2x\\\\7=x

The value of x is 7. Insert the value of x into the given length of AC:

AC=3(7)-7

Simplify multiplication:

AC=21-7

Subtract:

AC=14

Therefore, the length of the line segment AC is 14.

:Done

8 0
3 years ago
Which equation shows the quadratic formula used correctly to solve 5x2 + 3x – 4 = 0 for x? x = StartFraction negative 3 plus-or-
Brrunno [24]

Answer: FIRST OPTION

Step-by-step explanation:

<h3> The missing picture is attached.</h3>

By definition, given a Quadratic equation in the form:

ax^2+bx+c=0

Where "a", "b" and "c" are numerical coefficients and "x" is the unknown variable, you caN use the Quadratic Formula to solve it.

The Quadratic Formula is the following:

x=\frac{-b \±\sqrt{b^2-4ac} }{2a}

In this case, the exercise gives you this Quadratic equation:

5x^2 + 3x - 4 = 0

You can identify that the numerical coefficients are:

a=5\\\\b=3\\\\c= - 4

Therefore, you can substitute values into the Quadratic formula shown above:

x=\frac{-b \±\sqrt{b^2-4ac} }{2a}\\\\x=\frac{-3 \±\sqrt{(3)^2-4(5)(-4)} }{2(5)}

You can identify that the equation that shows the Quadratic formula used correctly to solve the Quadratic equation given in the exercise for "x", is the one shown in the First option.

6 0
3 years ago
Read 2 more answers
11. Write 343 with an exponent by using<br> 7 as the base.
dimulka [17.4K]

Answer:

343 can be written as

7 {}^{3}

Step-by-step explanation:

since we know,

343 = 7 × 7 × 7

so, we can write 343 as cube of 7

hence,

343 = 7 {}^{3}

5 0
3 years ago
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