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4 years ago

A motorboat and a pwc are meeting head-on. which one is the stand-on vessel?

1 answer:

5 0

This is a boating question not really a physics questions, but googling the rules says the motorboat is the stand on vessel. The pwc is, by class, lighter than the motorboat so it has more maneuverability and thus should be the one to change course. The motorboat is the stand on vessel, so it keeps it's course and speed unchanged.

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When we stand on loose sand, our feet go deep into the sand but when we lie down on the sand our body does not go that deep in t

wlad13 [49]

When you lay down your weight is distributed over a much larger surface area than while standing. You are putting a much greater force on a much smaller area standing.

7 0

4 years ago

What is the moment of inertia of a cube with mass M=0.500kg and side lengths s=0.030m about an axis which is both normal (perpen

prisoha [69]

Answer:

The moment of inertia I is

I = 2.205x10^-4 kg/m^2

Explanation:

Given mass m = 0.5 kg

And side lenght = 0.03 m

Moment of inertia I = mass x radius of rotation squared

I = mr^2

In this case, the radius of rotation is about an axis which is both normal (perpendicular) to and through the center of a face of the cube.

Calculating from the dimensions of the the box as shown in the image below, the radius of rotation r = 0.021 m

Therefore,

I = 0.5 x 0.021^2 = 2.205x10^-4 kg/m^2

8 0

4 years ago

Please answer the following question.

Elina [12.6K]

Doppler Shift lets you see a star A. Move back and forth

<h3>What is Doppler Shift?</h3>

This refers to the frequency change of a wave in relation to an observer as it moves back and forth.

Hence, we can see that the thing which astronomers can learn from the Radial Velocity Method is D. Period of orbit and minimum mass of a planet as it measures the wavelengths of absorption lines in its spectrum.

Read more about doppler shift here:

brainly.com/question/4052291

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7 0

2 years ago

A motorcycle that is slowing down uniformly covers 2.0 successive km in 80 s and 120 s, respectively. Calculate (a) the accelera

8090 [49]

Answer:

acceleration = -0.042 m/s²

velocity at beginning = 14.167 m/s

velocity at end = 5.7183 m/s

Explanation:

given data

distance d1 = 1 km

distance d2 = 2 km

time t1 = 80 s

time t2 = 120 s + 80s = 200 s

to find out

acceleration and velocity at beginning and end

solution

we apply here law of motion that is

d = vt + 1/2×at²

put value

1000 = v(80) + 1/2×a(80)² ........................1

and

2000 = v(200) + 1/2×a(200)² ........................2

so from equation 1 and 2 we get a and v

a = -0.042 m/s² and

v = 14.167 m/s

so by kinematic final velocity will be

V² = v² + 2ad

V² = (14.167)² + 2×(-0.042)×(2000)

V² = 32.70

V = 5.7183 m/s

acceleration = -0.042 m/s²

velocity at beginning = 14.167 m/s

velocity at end = 5.7183 m/s

8 0

3 years ago

ad for the distance from the sun tothe earth is 1.5 x 10"m. how long does it take for light from ths sun to reach the eath? give

Alexandra [31]

Answer:

About 8.3 minutes

Explanation:

Use the formula for velocity as the distance covered by the light divided the time it takes: $[tex]velocity=\frac{distance}{time}$ [/tex]

Use the information about the speed of light in vacuum: $300000000 \frac{m}{s} = 3*10^{8} \frac{m}{s}$

and the information you are given regarding the distance between Sun and Earth: $1.5 * 10^{11} m$

to solve the first velocity equation for the unknown time "t":

$velocity=\frac{distance}{time} \\3*10^8\frac{m}{s} =\frac{1.5*10^11 m}{t} \\t=\frac{1.5*10^11 }{3*10^8} s= 500 s$

we can convert second into minutes by dividing by 60: 500 s = 500/60 minutes = 8.3333... minutes

5 0

3 years ago