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3 years ago

A stationary block resting on the ground is pulled up with a tension force of 100N, but does not leave the ground.

Physics

1 answer:

tekilochka [14]3 years ago

6 0

Answer:

The normal force the ground exerts on the block, F = -300 N

Explanation:

Given data,

The block pulled up with a tension force, T = 100 N

The weight of the block, W = 300 N

The weight of the block is due to the force of attraction of gravitation.

The surface exerts a force that is equal and opposite to the force acting on the block due to gravitation.

The weight of the block,

W = mg

300 N

The normal force the ground exerts on the block,

F = - mg

= - 300 N

Hence, the normal force the ground exerts on the block, F = -300 N

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Lunna [17]

Answer:

Angle of projection from the horizontal will be $21.80^{\circ}$

Explanation:

We have given that range of the projectile is 10 times the height of the projectile

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Range of the projectile is equal to $R=\frac{u^2sin2\Theta }{g}$

And height of the projectile is equal to $h=\frac{u^2sin^2\Theta }{2g}$

Now according to question range is 10 times of height

So $\frac{u^2sin2\Theta }{g}=10\times \frac{u^2sin^2\Theta }{2g}$

$sin2\Theta =5sin^2\Theta$

$2sin\Theta cos\Theta =5sin^2\Theta$

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3 years ago

Does a can opener make work easier by increasing force, increasing distance, or changing direction?

ivann1987 [24]

A can opener makes work easier by increasing force.

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Calculate the wavelength of the electromagnetic radiation required to excite an electron from the ground state to the level with

anastassius [24]

Answer:

2.11 m

Explanation:

Given data

h=6.626× $10^{-34\\}$ (plank constant)

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n=5-1

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λ=? (Wavelength)

solution

The energy stored in an electron at a specified level is given by;

E= $h^{2}$ × $n^{2}$ ÷8m $l^{2}$ ..........(1)

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To find E

putting the value of given data in eq(1)

E=9.41× $10^{-16}$

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λ=hc/E............................(2)

c=3× $10^{8}$ (speed of light)

putting the value in eq 2 to find wavelength

λ=2.11 m

Note:

There is a chance in calculation error. but the method is correct to solve the problem.

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