-2/3-(-1 1/3) =
-2/3 + 1 1/3 =
4/3 - 2/3 =
<em>2/3</em>
12 - (-5) =
12 + 5 =
<em>17</em>
-1 - (-6) =
-1 + 6 =
6 - 1 =
<em>5</em>
-3 3/8 - 7/8 =
27/8 - 7/8 =
20/8 =
2 4/8 =
<em>2</em><em> </em><em>1/2</em>
X=numbers of hammers
y=numbers of scewdrivers
f(x,y)= total cost in $
f(x,y)=11x+6.65y
f(4,7)=4(11)+6.65(7)=44+46.55=90.55
Sol: an expresion for the total cost of the tools is f(x,y)=11x+6.65 y;
x=number of hammers
y= number of scewdrivers.
The total cost is $90.55
Answer:
The correct answer is A. 9.4 inches.
Step-by-step explanation:
Given that the volume of a boys' basketball is 434 cubic inches, and Dan would like to get a ball with half the volume for his son, to determine what is the diameter of the ball that Dan will buy for his son, the following calculation has to be done, knowing that the volume of a sphere is four thirds multiplied by pi multiplied by the radius cubed:
4/3 x 3.14 x X ^ 3 = 434
4.186 x X ^ 3 = 434
X ^ 3 = 434 / 4.186
X = 3√ 103.662
X = 4.7
In turn, since the radius of a sphere is equal to half its diameter, the diameter of the basketball is 9.4 inches (4.7 x 2).
Answer:
3/16
Step-by-step explanation:
Monica has a 24-inch square frame.
There are 4 equal sides.
Hence, length of each side=24/4 inch
= 6 inch
She paints 3/4 of one side of the frame blue.
i.e. she paints 
inch
Total part to be painted=24 inch
Hence, fraction of the frame Monica painted blue is:
Answer:
Step-by-step explanation:
![x^2 > 100\\\\\mathrm{For\:}u^n\:>\:a\\\mathrm{,\:if\:}n\:\mathrm{is\:even}\mathrm{\:then\:}u\:\:\sqrt[n]{a}\\\\x\sqrt{100}\\\\\sqrt{100}=10\\\\x10](https://tex.z-dn.net/?f=x%5E2%20%3E%20100%5C%5C%5C%5C%5Cmathrm%7BFor%5C%3A%7Du%5En%5C%3A%3E%5C%3Aa%5C%5C%5Cmathrm%7B%2C%5C%3Aif%5C%3A%7Dn%5C%3A%5Cmathrm%7Bis%5C%3Aeven%7D%5Cmathrm%7B%5C%3Athen%5C%3A%7Du%5C%3A%3C%5C%3A-%5Csqrt%5Bn%5D%7Ba%7D%5C%3Aor%5C%3Au%5C%3A%3E%5C%3A%5Csqrt%5Bn%5D%7Ba%7D%5C%5C%5C%5Cx%3C-%5Csqrt%7B100%7D%5Cquad%20%5Cmathrm%7Bor%7D%5Cquad%20%5C%3Ax%3E%5Csqrt%7B100%7D%5C%5C%5C%5C%5Csqrt%7B100%7D%3D10%5C%5C%5C%5Cx%3C-10%5Cquad%20%5Cmathrm%7Bor%7D%5Cquad%20%5C%3Ax%3E10)
