1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
babymother [125]
3 years ago
14

Find the length of the arc in red shown below

Mathematics
1 answer:
Svetllana [295]3 years ago
6 0

Answer:

3.92699

Step-by-step explanation:

3.92699

Length of arc. Not sure what "in terms of pi means..."

You might be interested in
The distance from Antville to Beetleton is 60 km.
serious [3.7K]

Answer:

i. Time = 2 hours.

ii. Average speed for the whole journey = 25 km/h

Step-by-step explanation:

Distance from Antville to Beetleton = 60 km

Mr. Caterpillar's speed = 30 km/h

Speed = \frac{distance}{time}

⇒ time = \frac{distance}{speed}

            = \frac{60}{30}

            = 2

time = 2 hours

It would take Mr. Caterpillar 2 hours to travel from Antville to Beetleton at that speed.

On his return journey, his average speed is 20 km/h. Therefore;

average speed for the whole journey = \frac{30 + 20}{2}

                                                 = \frac{50}{2}

                                                 = 25

average speed for the whole journey = 25 km/h

8 0
3 years ago
Which statement about the graph is true? On a coordinate plane, a line goes through points (0, 2), (2, 3), (4, 4), (6, 5). The g
Tema [17]

The answer is C. The graph does not show a proportional relationship because each point written as a ratio gives a different value.

Hope this helped! If it didn't please tell me what went wrong so I can fix it.

6 0
2 years ago
Read 2 more answers
Kay donates twice what Ed donates.
Leviafan [203]

Answer:

ed is the independent and kay is the dependent.

Step-by-step explanation:

I dont know about the rest sorry

7 0
2 years ago
Algebra about ages please help
valentinak56 [21]

To solve this problem, we need to recognize that Harry's age is given as "n".  We can use this value and the given information to write expressions representing each person's age.

For Example, Jo is 2 years older than Harry and Harry's age is represented by the variable n.  This means that n (Harry's age) plus 2 would equal Jo's age.  This can be represented by the expression: n +2.

Next, we know that Kate is twice as old as Jo, and Jo's age is represented by the expression n+2.  This means that 2 times Jo's age would be equal to Kate's age, or Kate's age = 2(n+2) or 2n +4.

Therefore, your answer is that Jo's age is n + 2 and Kate's age is 2n + 4.

Hope this helps!

3 0
3 years ago
Insert <, >, or = in the appropriate space to make a true statement.
Harman [31]

Answer:

  >

Step-by-step explanation:

1 - 3 ?? -4

-2 ?? -4

The appropriate symbol for this ?? relation is >.

  1 -3 > -4

6 0
3 years ago
Other questions:
  • Equivalent ratio word problems (basic)
    12·1 answer
  • carmen draws this area model to help her divide 1800 by 9. she say the quotient is 20. does carmen model make sense​
    6·2 answers
  • Please help! Whoever does will<br> Be marked branliest answer
    13·1 answer
  • A man wants to take a goat, a bag of cabbage, and a wolf over to an island. His boat will only hold him and one animal or item.
    13·1 answer
  • In 10 months 62.6 gallons were used find the unit rate
    10·2 answers
  • Can someone please help me with this question
    13·1 answer
  • The WSJ lists a bond as Acme 9s13 and the price as 89.875. If your required rate of return is 10%, would you buy one of these bo
    14·1 answer
  • Help me out <br>Answer required ​
    6·1 answer
  • The random variable X takes on the values of 2, 5, n, and 15. The probability distribution of X is shown in the following table
    13·2 answers
  • a garage sells 86 more red cars Than blue cars the garage sells 1048 blue cars how many blue and red cars do they sell?​
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!