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V=(1/3)hpir^2
lets say this is original, undoubled volume
so o=v=(1/3)hpir^2
so for new volume, or n, that is r to 2r, doubled radius
n=(1/3)hpi(2r)^2
n=(1/3)hpi4r^2
n=4((1/3)hpir^2)
remmember that o=(1/3)hpir^2
n=4(o)
it is 4 times the old one
Answer:
B. y = -5/2x +3/2
Step-by-step explanation:
5x + 2y = 3
We want to get this in the form
y = mx +b where m is the slope and b is the y intercept
Subtract 5x from each side
5x -5x+ 2y =-5x+ 3
2y = -5x+3
Divide by 2
2y/2 = -5x/2 +3/2
y = -5/2 x +3/2
Answer:
2/5=0.4
0.4*11.25=4.5
Step-by-step explanation:
2:5
4:10
66:165
Is that correct?