The leftmost line segment has a domain of -4 ≤ x < -1, or [-4, 1).
The central line segment has a domain of -1 ≤ x ≤ 2, or [-1, 2].
The rightmost line segment has a domain of 2 < x ≤ 5, or (2, 5].
Overall, this function has a domain of
[-4, 1) U [-1, 2] U (2, 5]
(where U means "union" in the set-theoretic notion)
But this also simplifies to the interval [-4, 5].
These correspond to the <u>first</u> and <u>last</u> choices.
Answer:
0.1151 = 11.51% probability of completing the project over 20 days.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Expected completion time of the project = 22 days.
Variance of project completion time = 2.77
This means that ![\mu = 22, \sigma = \sqrt{2.77}](https://tex.z-dn.net/?f=%5Cmu%20%3D%2022%2C%20%5Csigma%20%3D%20%5Csqrt%7B2.77%7D)
What is the probability of completing the project over 20 days?
This is the p-value of Z when X = 20, so:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{20 - 22}{\sqrt{2.77}}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B20%20-%2022%7D%7B%5Csqrt%7B2.77%7D%7D)
![Z = -1.2](https://tex.z-dn.net/?f=Z%20%3D%20-1.2)
has a p-value of 0.1151.
0.1151 = 11.51% probability of completing the project over 20 days.
Answer:
Each candy bar was $3
Step-by-step explanation:
You subtract the 3 dollar soda from the total to find out how much he spent on candy bars all together.Then, you divide that number by how many candy bars he purchased, 6 to get your answer, $3
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Answer:
1/π
Step-by-step explanation:
r = the side of the square and the radius of the circle
square area = r∧2/π·r∧2
r∧2 should cancel each other in the numerator and denominator.
The result is 1/π