Answer
given,
mass of the package = 12 kg
slides down distance = 2 m
angle of inclination = 53.0°
coefficient of kinetic friction = 0.4
a) work done on the package by friction is
W_f = -μk R d
= -μk (mg cos 53°)(2.0)
=-(0.4)(8.0 )(9.8)(cos 53°)(2.0)
= -37.75 J
b)
work done on the package by gravity is
W_g = m (g sin 53°) d
= (8.0 )(9.8 )(sin 53°)(2.0 )
=125.23 J
c)
the work done on the package by the normal force is
W_n = 0
d)
the net work done on the package is
W = -37.75 + 125.23 + 0
W = 87.84 J
This should help,
Search up the Scientific method and lookup for the meaning of each word.
I can't help with all of it but this should help for most
Answer:
Differences are listed below:
Explanation:
Weight: Plastic can weigh appreciably much less than than metal.A plastic part weighs approximately one-sixth of the same part in steel.
Chemical resistance:Plastic are much less likely to suffer chemical attack and don not corrode.
Machinability: Plastic are much more easier to cut through than metal.
Product life: The life span for plastic is longer than of the metals in many applications.
Cost: The cost of plastic raw materials is appreciably less than of the metals.
Heat: Plastic are less heat resistive than metals.
Ultraviolet light can degrade the plastics soon.
Strength: Metal provides more strength than the plastic.
The force of gravity is equal to the mass times centripetal acceleration.
Fg = m v^2 / r
The force of gravity is defined by Newton's law of universal gravitation as:
Fg = mMG / r^2
Therefore:
mMG / r^2 = m v^2 / r
MG / r = v^2
v increases as r decreases. So the planet with the smallest orbit (closest to the sun) will have the highest orbital velocity. Of the four options, that's Mercury.
One should never anchor in a narrow channel, until unless required very importantly. One should stay to the starboard side, and use a prolonged blast. The announcement must be done to alarm the nearby vessels, about your approach. The vessel should be kept at the outer limit of the starboard side.
