What is the force required to stretch a spring whose constant value is 35 N/m by an amount of 0.25 m?
1 answer:
You might be interested in
Answer:
Explanation:
<u>Given the following data;</u>
Initial velocity = 0 (since the stone is starting from rest).
Final velocity = 32 m/s
Acceleration = g = 10 m/s²
Time = 3.2 seconds
To show that the speed of the stone when it hits the ground is 32 m/s, we would use the first equation of motion;
Where;
- V is the final velocity.
- U is the initial velocity.
- a is the acceleration.
- t is the time measured in seconds.
Substituting into the formula, we have;
<em>Proven: 32 m/s = 32 m/s</em>
Answer:
Explanation:
Mass
Diameter
Length
Generally the equation for Volume flow rate is mathematically given by
Generally the equation for Friction factor is mathematically given by
Where Re
Re=Reynolds Number
Therefore
Generally the equation for Friction factor is mathematically given by
Where