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lidiya [134]
3 years ago
6

Recall that the spring constant is inversely proportional to the number of coils in the spring, or that shorter springs equate t

o stiffer springs. An object is attached to the lower end of a 14-coil spring that is hanging from the ceiling. The spring stretches by 0.174 m. The spring is then cut into two identical springs of 7 coils each. As the drawing shows, each spring is attached between the ceiling and the object. By how much does each spring stretch?
Physics
1 answer:
ruslelena [56]3 years ago
7 0

Answer:

x_1= 0.0425m

Explanation:

Using the tension in the spring and the force of the tension can by describe by

T = kx

, T = mg

Therefore:

m*g = k*x

With two springs, let, T1 be the tension in each spring,  x1 be the extension of each spring.  The spring constant of each spring is 2k so:

T_1 = 2k*x_1

2T_1 = m*g=4k x_1

Solve to x1

x_1=\frac{m*g}{4k}

x_1=\frac{k*x}{4*k}

x_1=\frac{x}{4}

x_1 = 0.170 / 4

x_1= 0.0425m

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