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natali 33 [55]
3 years ago
7

*PLEASE HELP WILL GIVE BRAINLIEST*

Physics
1 answer:
Lorico [155]3 years ago
4 0

More mass will in turn create more force in a collision.


The number of marbles in a collision will affect the outcome because they could bounce off each other and what not.

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A circular-motion addict of mass 80 kg rides a Ferris wheel around in a vertical circle of radius 10 m at a constant speed of 6.
bekas [8.4K]

Answer with Explanation:

We are given that

Mass=80 kg

Radius,r=10 m

Speed,v=6.1 m/s

a.Time period,T=\frac{2\pi r}{v}=\frac{2\pi\times 10}{6.1}=10.3 s

b.F_N=mg-\frac{mv^2}{r}

Substitute the values

F_N=80\times 9.8-\frac{80\times(6.1)^2}{10}=486 N

c.F_N=mg+\frac{mv^2}{r}

Substitute the values

F_N=80\times 9.8+\frac{80\times (6.1)^2}{10}=1081.7 N

7 0
3 years ago
A heat engine does 9200 J of work per cycle while absorbing 22.0 kcal of heat from a hightemperature reservoir. What is the effi
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Answer: 9.9%

Explanation: efficiency = (work output /work input) × 100

Note that, 1 kilocalorie = 4184 joules, hence 22kcal = 22× 4184 = 92048 joules.

Work output = 9200 j and work input = 92048 j

Efficiency = (9200/92048) × 100 = 0.099 × 100 = 9.9%

4 0
3 years ago
Recording the location of a star requires a measurement of:
Scorpion4ik [409]

Answer:

It requires a measurement of altitude azimuth time.

Hope this helps, if it did, please give it a brainliest.

7 0
2 years ago
A 15 kilogram mass is traveling with a velocity of 2.7m/s. What is the object's kinetic energy?
Usimov [2.4K]

Answer:

KE=1/2*m*v^2

KE=1/2*15*2.7^2

KE=54.675 J

Explanation:

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3 years ago
A whistle you use to call your hunting dog has a frequency of 21 kHz, but your dog is ignoring it. You suspect the whistle may n
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The Doppler effect is the right concept to solve this problem. The Doppler effect is understood as the change in apparent frequency of a wave produced by the relative movement of the source with respect to its observer. Mathematically it can be described as,

f = (1-\frac{v_0}{v})f_0

Here,

f_0 = Frequency of the sound from the Whistle

f = Frequency of sound heard

v = Speed of the sound in the Air

Replacing we have that

1- \frac{v_0}{343} = \frac{20kHz}{21kHz}

\frac{v_0}{343} = 1-\frac{20}{21}

\frac{v_0}{343} = \frac{1}{21}

v_0 = \frac{1}{21}(343)

v_0 = 16.33m/s

Therefore the minimum speed to know if the whistle is working is 16.33m/s

3 0
3 years ago
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