All categories

3 years ago

PLEASE HELP WILL GIVE BRAINLIEST

Physics

1 answer:

Lorico [155]3 years ago

4 0

More mass will in turn create more force in a collision.

The number of marbles in a collision will affect the outcome because they could bounce off each other and what not.

You might be interested in

How would you describe the behavior of particles in a solid?

Minchanka [31]

How would you describe the behavior of particles in a solid?

4 0

2 years ago

Read 2 more answers

Compare and contrast electric potential energy and electric potential difference? Explain.

forsale [732]

Answer:

Electric Potential Energy:

The energy that is needed to move a charge against an electric firld is called Electric Potential Energy

Electric Potential Difference:

The amount of work done in carrying a unit charge from one point to an other in an electric field is called Electric Potential Difference.

Relation:

Relation between Electric potential and electrical potential energy is given by

$\delta V=\frac{PE}{q}$

Here PE represents Electric potential energy

and $\delta V$ is Electric potential difference

it means electric potential difference is the difference in electric potential energy divided by the charge.

6 0

2 years ago

A proton traveling along the x-axis enters a region at x = 0 where the x-component of the electric field is given by E = Ao/x1/2

storchak [24]

.Answer:

The value of the work done is $\bf{ 5.29 qA_{0}}$ .

Explanation:

When a charged particle having charge $q$ is moving through an electric field $E$ , the net force ( $F$ ) on the charge is

$F = qE~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)$

and the work done ( $W$ ) by the particle is

$W = \int\limits^x_0 {F} \, dx ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)$

Given, $E = \dfrac{A_{0}}{x^{1/2}}$ .

Substitute the value of electric field in equation (1) and then substitute the result in equation (2).

$W &=& \int\limits^7_0 {q\dfrac{A_{0}}{x^{1/2}}} \, dx \\&=& qA_{0} \int\limits^7_0 {x^{-1/2}} \, dx \\&=& 2qA_{0}[x^{1/2}]_{0}^{7}\\&=& 5.29 qA_{0}$

7 0

3 years ago

Suppose that two Scientists use different measurement systems in their work. What problems might arise if they shared their data

alexandr402 [8]

In order to understand the results of another scientist's work, any scientist
who reads the report MUST understand the measurement system in which
the result is described. Otherwise the result is meaningless to him.

3 0

3 years ago

In a photoelectric effect experiment, electrons emerge from a copper surface with a maximum kinetic energy of 1.10 eV when light

Sladkaya [172]

Answer:A) 220 nm

Explanation:

Given

Maximum Kinetic Energy $K.E.=1.10 eV$

Work Function $W=4.65 eV$

from Einstein Equation

$h\mu =W+K.E.$

$h\cdot \frac{c}{\lambda }=W+K.E.$

$h\cdot \frac{c}{\lambda }=4.65+1.10$

$6.626\times 10^{-34}\cdot \frac{3\times 10^8}{\lambda }=5.75$

$1 eV=1.6\times 10^{-19} J$

thus $5.75 eV=9.2\times 10^{-19} J$

$\lambda =\frac{6.626\times 10^{-34}\time 3\times 10^8}{9.2\times 10^{-19}}$

$\lambda =216.06 nm\approx 220 nm$

6 0

3 years ago

*PLEASE HELP WILL GIVE BRAINLIEST*

PLEASE HELP WILL GIVE BRAINLIEST