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Anna11 [10]
3 years ago
5

Help in this pleasee

Mathematics
1 answer:
Ulleksa [173]3 years ago
6 0
It’s the 4th one lol
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Solve the system of linear equations. separate the x- and y- values with a coma.
kobusy [5.1K]
Solve the following system:
{7 x - 3 y = 37 | (equation 1)
{14 x + 11 y = 23 | (equation 2)
Swap equation 1 with equation 2:
{14 x + 11 y = 23 | (equation 1)
{7 x - 3 y = 37 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{14 x + 11 y = 23 | (equation 1)
{0 x - (17 y)/2 = 51/2 | (equation 2)

Multiply equation 2 by 2/17:
{14 x + 11 y = 23 | (equation 1)
{0 x - y = 3 | (equation 2)

Multiply equation 2 by -1:
{14 x + 11 y = 23 | (equation 1)
{0 x+y = -3 | (equation 2)
Subtract 11 × (equation 2) from equation 1:
{14 x+0 y = 56 | (equation 1)
{0 x+y = -3 | (equation 2)

Divide equation 1 by 14:
{x+0 y = 4 | (equation 1)
{0 x+y = -3 | (equation 2)
Collect results:
Answer: {x = 4
               {y = -3

4 0
3 years ago
Convert 4 5/7 to an improper fraction
Musya8 [376]

Answer:

33/7

Step-by-step explanation:

8 0
3 years ago
Walt grew 10 cm in 1 year. He is now 1.6 m tall. How tall was he 1 year ago?
wlad13 [49]
10cm is the same as point 1 meter so 1.6 minus point 1 is 1.5

i hope this hp u
8 0
3 years ago
Read 2 more answers
Can I get help with this? Thanks! :)
ycow [4]

Answer:

The answer is 17

Step-by-step explanation:

8^2+15^2=c^2

64+225=c^2

289=c^2

Square root both sides

c=17

8 0
3 years ago
What is the slope of the line that passes through the points
Oksana_A [137]

The slope is ∞ , line is a vertical line parallel to y axis.

<h3>What is a Straight Line Function ?</h3>

A straight line function is a function that can be represented by y = mx +c , where m is the slope of the line and c is the intercept on the y axis.

There are two points given for a line ,

The slope is represented  by

\rm m = \dfrac{y_2 -y_1}{x_2 -x_1}\\\\m = \dfrac{31-6}{1-1}

m = ∞

which means the line is a vertical line parallel to y axis.

To know more about Straight Line Function

brainly.com/question/21145944

#SPJ1

4 0
1 year ago
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