Answer:
Step-by-step explanation:
Domain of a function is a set of x-values (input values) for which the function is defined.
Range of a function is a set of y-values (output values) for the given set of input values.
7). Domain → (-∞, ∞)
Range → (-∞, ∞)
8). Domain → (-∞, ∞)
Range → [-2, ∞)
9). Domain → [-2, 2]
Range → [-3, 3]
10). Domain → (-∞, ∞)
Range → [-1, 1]
All are correct except the bottom, it would just be 4.23 since there are no zeroes, any number times 1 is itself
P² - 12 p - 13 = 0
Δ = ( -12)² - 4 ( 1 * - 13)
Δ = 144 + 52
Δ = 196 = 14²
x₁ = (- ( -12) + 14 ) / 2 = 26/2 = 13
x₂ = ( - ( -12) - 14) /2 = - 2 /2 = - 1
S = 13
Answer:
Solution given:
For 1st
x²=71
For x=±
and
For 2nd
x³=71
For x=±![\sqrt[3]{71}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B71%7D)
So answer is:
In first row
<u>Solution to x²=71</u>
In second row
<u>Solution to </u><u>x³</u><u>=71</u>
In third row
<u>neither</u>
In forth row
<u>Solution to x³=71</u>
0.04 is 1/10 of 0.4
0.4 x 0.10 = 0.04
hope this helps
