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Marat540 [252]
3 years ago
15

The diagram shows a circle in a square 6cm calculate the shaded area take pi to 3.142

Mathematics
1 answer:
Kaylis [27]3 years ago
5 0

The question is incomplete (as there's no attachment to support the question).

However, I'll base my calculations base on the attached diagram to this solution.

Answer:

Shaded Area = 7.722 cm²

Step-by-step explanation:

Given.

Side of the square = 6cm

π = 3.142

Required:

Area of shaded region

First, the area of the square needs to be calculated.

Area of a square = Length * Length

Area = 6cm * 6cm

Area = 36cm²

Then we calculate the area of the circle.

To calculate this, we need to get the radius of the circle.

If the length of the sides of the square is 6 cm, then the diameter of the square is also 6 cm.

Now that we have the diameter, the radius can be calculated.

Radius, R = ½D (where R and D represent radius and diameter, respectively)

So,

R = ½ * 6 cm

R = 3cm

Area of a circle = πr²

Area = 3.142 * 3²

Are = 3.142 * 9

Area = 28.278 cm²

The shaded area is then calculated by subtracting the area of the circle from the area of the square.

Shaded Area = Area of Square - Area of Circle

Shaded Area = 36cm² - 28.278cm²

Shaded Area = 7.722cm²

Hence, the shaded area 7.722 cm²

The question is incomplete (as there's no attachment to support the question).

However, I'll base my calculations base on the attached diagram to this solution.

Answer:

Shaded Area = 7.722 cm²

Step-by-step explanation:

Given.

Side of the square = 6cm

π = 3.142

Required:

Area of shaded region

First, the area of the square needs to be calculated.

Area of a square = Length * Length

Area = 6cm * 6cm

Area = 36cm²

Then we calculate the area of the circle.

To calculate this, we need to get the radius of the circle.

If the length of the sides of the square is 6 cm, then the diameter of the square is also 6 cm.

Now that we have the diameter, the radius can be calculated.

Radius, R = ½D (where R and D represent radius and diameter, respectively)

So,

R = ½ * 6 cm

R = 3cm

Area of a circle = πr²

Area = 3.142 * 3²

Are = 3.142 * 9

Area = 28.278 cm²

The shaded area is then calculated by subtracting the area of the circle from the area of the square.

Shaded Area = Area of Square - Area of Circle

Shaded Area = 36cm² - 28.278cm²

Shaded Area = 7.722cm²

Hence, the shaded area 7.722 cm²

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4 0
2 years ago
Please help me with these?!
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1. We have the formula for the volume of sphere: V= \frac{4 \pi }{3}r^3
where 
V is the volume
r is the radius 
We know from our problem that the volume of our spherical balloon is 100in^3, so V=100in^3. Lets replace that value in our formula and solve for r:
100in^3= \frac{4 \pi }{3}r^3
3(100in^3)=4 \pi r^3
300in^3=4 \pi r^3
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We can conclude that the radius of our spherical balloon is approximately 3 inches long. Therefore, the correct answer is A. 3 in.

2. Lets simplify each one of the expressions first:
F. \sqrt{x^2} since the radicand is elevated to the same number as the index of the radical, we can cancel the radical and the exponent:
\sqrt{x^2} =x
Since x\ \textgreater \ 0, this expression is equal to x.
G. \frac{1}{2}  \sqrt[3]{8x^3} 8 can be expressed as 8=2*2*2=2^3, so we can rewrite our radicand:
\frac{1}{2} \sqrt[3]{8x^3} =\frac{1}{2} \sqrt[3]{2^3x^3} = \frac{1}{2} \sqrt[3]{(2x)^3}
Since the radicand is elevated to the same number as the index of the radical, we can cancel the radical and the exponent:
\frac{1}{2} \sqrt[3]{(2x)^3}= \frac{1}{2} (2x)
Now, we can cancel the 2 in the denominator with the one in the numerator:
\frac{1}{2} (2x)=x
Since x\ \textgreater \ 0, this expression is equal to x.
H. \sqrt[3]{-x^3} The radicand is elevated to the same number as the index of the radical, so we can cancel the radical and the exponent:
\sqrt[3]{-x^3}=-x
Since x\ \textgreater \ 0, this expression is NOT equal to x.

We can conclude that the correct answer is H. \sqrt[3]{-x^3}.

3. The fourth root of - \frac{16}{81} is \sqrt[4]{ -\frac{16}{81} }. Remember that negative numbers don't have real even roots since a number raised to an even exponent  is either positive or 0. Since 4 is even and - \frac{16}{81} is negative, we can conclude that - \frac{16}{81} has not a real fourth root. 

The correct answer is D. no real root found.

4. This time we are going to take a different approach.  We are going to simplify \sqrt{a^2(x+a^2)} first, and then, we are going to compare the result with our given options:
\sqrt{a^2(x+a^2)}
Lets apply the product rule for a radical \sqrt[n]{ab} = \sqrt[n]{a}  \sqrt[n]{b}:
\sqrt{a^2(x+a^2)} = \sqrt{a^2}  \sqrt{x+a^2}
Notice that in our first product the radicand is raised to the same number as the index, so we can cancel the radical and the exponent:
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We can conclude that the correct answer is F. a \sqrt{x+a^2}

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\sqrt{4x^2y^4}
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\sqrt{4x^2y^4} = \sqrt{4} \sqrt{x^2}   \sqrt{y^4}
Notice that \sqrt{4} =2, so:
\sqrt{4} \sqrt{x^2} \sqrt{y^4} =2 \sqrt{x^2}  \sqrt{y^4}
Notice that y^4=(y^2)^2, so we can rewrite our expression:
2 \sqrt{x^2} \sqrt{y^4}=2 \sqrt{x^2}  \sqrt{(y^2)^2}
Applying the radical rule \sqrt[n]{a^n} =a:
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We can conclude that this statement is TRUE.
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If x= \frac{a}{b} and b\ \textgreater \ a, x^4 will always be smaller than x^2. Therefore, we can conclude that this statement is FALSE.

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3 years ago
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Step-by-step explanation:

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2 years ago
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Answer:

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b) Second partial quotient would be 8 as 31 x 8 = 248

5 0
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