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morpeh [17]
3 years ago
8

Which letter on the diagram below represents the trough of a wave?

Physics
2 answers:
Nikitich [7]3 years ago
8 0

A would be the wavelength, C would be a crest, D would be the amplitude, leaving B which is the trough.

marusya05 [52]3 years ago
8 0

Answer: B. B

Explanation:

The trough is B because it is the "minimum" amplitude of a wave since amplitude is D which is the displacement of wave from its initial position. The minimum value of the amplitude will be at B which is the trough.

Note that the maximum value of the amplitude will be the crest which at C.

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Which type of electromagnetic radiation is used to keep food warm?
n200080 [17]

Answer:

A. infrared

Explanation:

Heat lamps used to keep foods warm are infrared on the light spectrum

7 0
3 years ago
Consider the same roller coaster. It starts at a height of 40.0 m but once released, it can only reach a height of 25.0 m above
poizon [28]

Answer:

The magnitude of the frictional force between the car and the track is 367.763 N.

Explanation:

The roller coster has an initial gravitational potential energy, which is partially dissipated by friction and final gravitational potential energy is less. According to the Principle of Energy Conservation and Work-Energy Theorem, the motion of roller coster is represented by the following expression:

U_{g,1} = U_{g,2} + W_{dis}

Where:

U_{g,1}, U_{g,2} - Initial and final gravitational potential energy, measured in joules.

W_{dis} - Dissipated work due to friction, measured in joules.

Gravitational potential energy is described by the following formula:

U = m \cdot g \cdot y

Where:

m - Mass, measured in kilograms.

g - Gravitational constant, measured in meters per square second.

y - Height with respect to reference point, measured in meters.

In addition, dissipated work due to friction is:

W_{dis} = f \cdot \Delta s

Where:

f - Friction force, measured in newtons.

\Delta s - Travelled distance, measured in meters.

Now, the energy equation is expanded and frictional force is cleared:

m \cdot g \cdot (y_{1} - y_{2}) = f\cdot \Delta s

f = \frac{m \cdot g \cdot (y_{1}-y_{2})}{\Delta s}

If m = 1000\,kg, g = 9.807\,\frac{m}{s^{2}}, y_{1} = 40\,m, y_{2} = 25\,m and \Delta s = 400\,m, then:

f = \frac{(1000\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (40\,m-25\,m)}{400\,m}

f = 367.763\,N

The magnitude of the frictional force between the car and the track is 367.763 N.

7 0
4 years ago
A highway patrolman traveling at the speed limit is passed by a car going 20 mph faster than the speed limit. After one minute,
Oksi-84 [34.3K]

Answer:

It will take 40 seconds to catch the speeding car

Explanation:

Initial speed of the patrolman = 55 mph

after one minute speed of patrol man = 115 mph

now acceleration of patrolman is given by

a = \frac{v_f - v_i}{t}

a = \frac{115 - 55}{1/60} = 3600 m/h^2

now at this acceleration the distance covered by patrolman in "t" time is given as

d = v_i t + \frac{1}{2}at^2

d = 55t + 1800t^2

now we know the speed of the speeding car is given as

v' = (55+20) mph

now in the same time distance covered by it

d = 75 t

now since the distance covered is same

75 t = 55t + 1800 t^2

t = \frac{20}{1800} = \frac{1}{90} h

t = 40 seconds

7 0
4 years ago
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The answer should be B
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Cleats Chicks Bits and Bollards. Hope this helps
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