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morpeh [17]
2 years ago
8

Which letter on the diagram below represents the trough of a wave?

Physics
2 answers:
Nikitich [7]2 years ago
8 0

A would be the wavelength, C would be a crest, D would be the amplitude, leaving B which is the trough.

marusya05 [52]2 years ago
8 0

Answer: B. B

Explanation:

The trough is B because it is the "minimum" amplitude of a wave since amplitude is D which is the displacement of wave from its initial position. The minimum value of the amplitude will be at B which is the trough.

Note that the maximum value of the amplitude will be the crest which at C.

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Answer: It is increased to exert the pressure off the bywalls and on large area (brainliest pls)

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What best describes electrons
lyudmila [28]

Answer: A negatively charged particle that is found in atoms.

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The force F is expressed in terms of the mass “m” and acceleration “a” according to the
LekaFEV [45]

Answer:

F = [M] × [L1 T-2] = M1 L1 T-2.

Explanation:

Therefore, Force is dimensionally represented as M1 L1 T-2.

5 0
3 years ago
Which of these hazmat products are allowed in your FC?
aliina [53]

Answer: Hazmat products are allowed in your FC are:

  • A GPS unit (lithium batteries)
  • A subwoofer (magnetized materials)

Explanation:

Hazmat products consist of flammable, corrosive and harmful substances which are actually very hazardous to human health and environment.  

Hazardous material allowed in FC are as follows.

  • Magnetized material products like as speakers.
  • Non-spillable battery products like toy cars.
  • Lithium-ion battery containing products like laptops, mobile phones etc.
  • Non-flammable aerosol.

So, hazmat allowed products are GPS unit (lithium batteries) and subwoofer (magnetized materials).

Thus, we can conclude that hazmat products are allowed in your FC are:

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7 0
2 years ago
A long electric cable is suspended above the earth and carries a current of 345 A parallel to the surface of the earth. The eart
jok3333 [9.3K]

Answer:

0.906 N

Explanation:

Formula for magnetic force acting on current carrying cable:

F = IBLsin(\theta)

Where I = 345A is the current in the wire, B = 5.6*10^{-5} T is the magnetic magnitude generated by Earth. L = 46.9 m is the cable length. \theta = 88.2^o is the angle between vector B and cable direction.

F = 345*5.6*10^{-5}*46.9*sin(88.2^o)

F = 0.906 N

7 0
3 years ago
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