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hammer [34]
4 years ago
15

Which factors has the largest influence on the formation and direction of the asiatic monsoons?

Physics
1 answer:
cricket20 [7]4 years ago
8 0

Answer:

The factors which have the largest influence on the formation and direction of the asiatic monsoons are:

  1. Moisture-laden or <em>Humid </em> winds. The presence of abundant water bodies around the subcontinent such as  the Arabian Sea, Bay of Bengal, and Indian Ocean. These help moisture accumulate in the winds during the hot season.
  2. Droplet formation
  3. Land form barriers (that is Highlands) such as Himalayas, the western Ghats of India, and the Annamese Highlands of Vietnam

                 

Explanation:

The term monsoon comes from the Arabic word <em>mausim</em>, meaning

season.

As a meteorological term, monsoon refers to the directional shifting of winds from one season to the next.

It may also be referred to as a seasonal prevailing wind in the region of South and South-East Asia, blowing from the south-west between May and September and bringing rain (the wet monsoon ), or from the north-east between October and April (the dry monsoon).

Usually, the monsoon occurs when a humid wind blowing from the ocean toward the land in the summer shifts to a dry, cooler wind blowing seaward off the land in the winter, and it involves a full 180° direction change in the wind.

Orographic barriers (that is highlands in the path of the winds) force the winds to rise. Precipitation then occurs on the windward side of the highlands because of adiabatic cooling and condensation of the moist rising air.  

Cheers!

             

   

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Answer: 0.258

Explanation:

The resistance R of a wire is calculated by the following formula:

R=\rho\frac{l}{s}    (1)

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s is the transversal area of the wire. In this case is a circumference for both wires, so we will use the formula of the area of the circumference:

s=\pi{(\frac{d}{2})}^{2}  (2) Where d  is the diameter of the circumference.

For aluminium wire the diameter is  d_{Al}=2.5mm=0.0025m  and for copper is d_{Cu}=1.6mm=0.0016m

So, in this problem we have two transversal areas:

<u>For aluminium:</u>

s_{Al}=\pi{(\frac{d_{AL}}{2})}^{2}=\pi{(\frac{0.0025m}{2})}^{2}

s_{Al}=0.000004908m^{2}   (3)

<u>For copper:</u>

s_{Cu}=\pi{\frac{(d_{Cu}}{2})}^{2}=\pi{(\frac{0.0016m}{2})}^{2}

s_{Cu}=0.00000201m^{2}    (4)

Now we have to calculate the resistance for each wire:

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R_{Al}=2.65(10)^{-8}m\Omega\frac{12m}{0.000004908m^{2}}     (5)

R_{Al}=0.0647\Omega     (6)  Resistance of aluminium wire

<u>Copper wire:</u>

R_{Cu}=1.68(10)^{-8}m\Omega\frac{30m}{0.00000201m^{2}}     (6)

R_{Cu}=0.250\Omega     (7)  Resistance of copper wire

At this point we are able to calculate the  ratio of the resistance of both wires:

Ratio=\frac{R_{Al}}{R_{Cu}}   (8)

\frac{R_{Al}}{R_{Cu}}=\frac{0.0647\Omega}{0.250\Omega}   (9)

Finally:

\frac{R_{Al}}{R_{Cu}}=0.258  This is the ratio

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