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2 years ago

Most elements, with the exception of a few like hydrogen, want to have _________ electrons in the outer energy level. 6 8 10

1 answer:

7 0

8 because all elements after nitrogen have not only two energy levels, they also find it easier to just get rid of electrons than to absorb electrons to get to 8 electrons.

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A ball is thrown in the air from a height of 3 m with an initial velocity of 12 m/s. To the nearest tenth of a second, how long

wel

Answer: 0.3m/s

Step-by-step explanation:

Height/ velocity

3m/12m per sec

Time= 0.25metres per seconds

To the nearest tenth, 0.3m per seconds

5 0

2 years ago

Remember um 1 Calculate the midpoint of the segment joining (6.3) and (10, 15).

Sav [38]

(8, 9) will be the midpoint of the segment.
You can find this by applying the formula
(x1 + x2)/2 , (y1 + y2)/2

5 0

2 years ago

Read 2 more answers

What is the length (magnitude) of the vector (2,-1)?

KiRa [710]

Answer:

$\sqrt{5}$

Step-by-step explanation:

The given vector is represented by (2,-1).

This can be represented in general form as (x,y) where x=2 and y=-1.

Magnitude of the vector represented as (x,y) is given by $[\sqrt{x^{2}+y^{2}}\]$

Evaluating for the given values of x and y,

$\sqrt{2^{2}+(-1)^{2}}$ $=\sqrt{4+1}$

$=\sqrt{5}$

Length of the vector is $\sqrt{5}$

5 0

2 years ago

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding/Factoring

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

Step 2: Differentiate

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$