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xxTIMURxx [149]
2 years ago
15

Stefan was able to map \triangle ABD△ABDtriangle, A, B, D onto \triangle ABC△ABCtriangle, A, B, C. Stefan concluded: "I was able

to map \triangle ABD△ABDtriangle, A, B, D onto \triangle ABC△ABCtriangle, A, B, C using a sequence of rigid transformations, so the figures are congruent." What error did Stefan make in his conclusion? Choose 1 answer: Choose 1 answer: (Choice A) A Stefan didn't use only rigid transformations, so the figures are not congruent. (Choice B) B It's possible to map \triangle ABD△ABDtriangle, A, B, D onto \triangle ABC△ABCtriangle, A, B, C using a sequence of rigid transformations, but the figures are not congruent. (Choice C) C There is no error. This is a correct conclusion.
Mathematics
1 answer:
lianna [129]2 years ago
0 0

Answer: Stefan didn’t use only rigid transformations, so the figures are not congruent

Step-by-step explanation:

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Answer:

AB = 21

Step-by-step explanation:

So we have two triangles (AEB and ADC), and they're similar by AA

Now, you can find the ratio of similitude by checking AE/AD which is 14/26 = 7/13

AB/AC = 7/13

Take AB as x aight

x/x+18 = 7/13

x=21

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Answer:

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Step-by-step explanation:

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2 years ago
Which of the following is the solution to the inequality -5x + 20 < 130?
Masja [62]
The answer is B. x > -22


-5x + 20 < 130

-5x < 130 - 20

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2 years ago
What is each power of i with its multiplicative inverse.
pentagon [3]

Answer:

1) multiplicative inverse of i = -i

2) Multiplicative inverse of i^2 = -1

3) Multiplicative inverse of i^3 = i

4) Multiplicative inverse of i^4 = 1

Step-by-step explanation:

We have to find multiplicative inverse of each of the following.

1) i

The multiplicative inverse is 1/i

if i is in the denominator we find their conjugate

=1/i * i/i\\=i/i^2\\=We\,\, know\,\, that\,\, i^2 = -1\\=i/(-1)\\= -i

So, multiplicative inverse of i = -i

2) i^2

The multiplicative inverse is 1/i^2

We know that i^2 = -1

1/-1 = -1

so, Multiplicative inverse of i^2 = -1

3) i^3

The multiplicative inverse is 1/i^3

We know that i^2 = -1

and i^3 = i.i^2

1/i^3\\=1/i.i^2 \\=1/i(-1)\\=-1/i * i/i\\=-i/i^2\\= -i/-1\\= i

so, Multiplicative inverse of i^3 = i

4) i^4

The multiplicative inverse is 1/i^4

We know that i^2 = -1

and i^4 = i^2.i^2

=1/i^2.i^2\\=1/(-1)(-1)\\=1/1\\=1

so, Multiplicative inverse of i^4 = 1

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