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S_A_V [24]
3 years ago
7

Help ASAP due in 10 mins!!

Mathematics
1 answer:
sladkih [1.3K]3 years ago
4 0

Answer:

im guessing it is 48, -96

Step-by-step explanation:

going by the waves ;/

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IRINA_888 [86]
1: 0.5 and 50%

2: .2 and 20%

3: .75 and 75%

10: (1/10) and 10%

11: (3/5) and 60%

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3 years ago
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The steps used by Taylor to solve the equation 3(x - 2) = 6(2x + 1) + 6 are shown below:
alexandr1967 [171]
Both A and C are used within this problem. Distributing happens in the first and second step. Also, Inverse operations are used in nearly every step that is solving. 
6 0
3 years ago
How can you determine the type of the triangle based on the lengths of the sides in a triangle?
Mama L [17]

Answer:

You can determine the type of triangle using the following facts related to the converse of the pythag theorem

if a^2 + b^2 > c^2, then it is an obtuse triangle

if a^2+b^2<c^2, then it is an acute triangle

finally, if a^2+b^2=c^2, then it is a right triangle

<u><em>NOTE THAT C ALWAYS EQUALS THE LONGEST LENGTH OF THE TRIANGLE!!!</em></u>

6 0
3 years ago
On a certain hot summers day , 293 people used the public swimming pool. Daily prices are $1.50 for children and $2.50 for adult
fredd [130]

C = children

A = adults

293 = c + a

1.50c + 2.50a = 676.50

We can use substitution to solve:

c + a = 293 subtract a to get c = 293 - a

Plug this into the second equation:

1.50(293 - a) + 2.50a = 676.50

439.5 - 1.50a + 2.50a = 676.50

439.5 + 1a = 676.50

a = 237

Substitute this into the first equation:

293 = c + 237

56 = c

8 0
3 years ago
A particular brand of gasoline has a density of 0.737 g/ml at 25 ∘c. how many grams of this gasoline would fill a 13.4 gal tank
ruslelena [56]

Given, the density of a particular brand of gasoline = 0.737 g/ml.

13.4 gallon of tank given. We have to find the mass of gasoline to fill the tank.

First we will convert 13.4 gallon to ml.

We know that 1 gallon = 3.78541 litre

And 1 litre = 1000 ml

So we can write 1 gallon = (3.78541)(1000) ml = 3785.41 ml.

13.4 gallon = (3785.41)(13.4) ml = 50724.494 ml.

Let's take there is x grams of gasoline

We know that density = (mass/ volume) = \frac{x}{50724.494}

So we can write,

0.737 =\frac{x}{50724.494}

To find x we will multiply both sides by 50724.494. we will get,

(0.737)(50724.494) =(\frac{x}{50724.494}) (50724.494)

(0.737)(50724.494) = x

37383.95 = x

So we have got the required answer.

Mass of gasoline = 37383.95 grams.

5 0
4 years ago
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