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Monica [59]
3 years ago
8

Which expression is a possible leading term for the polynomial function graphed below?

Mathematics
2 answers:
allsm [11]3 years ago
7 0

Answer:

22x^{9} represent the given graph

Step-by-step explanation:

Given graph :  polynomial function graphed .

To find : Which expression is a possible leading term for the polynomial function .

Solution : We have given that

Graph with left end down and right end up.

By the end point behavior : If the degree of polynomial function is odd and leading coefficient is positive then left end is down and right end is up.

We can see from the given option 22x^{9}

It has degree = 9 (odd )

Leading coefficient  = 22 ( positive ).

Therefore, 22x^{9} represent the given graph.

Anon25 [30]3 years ago
6 0

Answer:

D, 22x^9

Step-by-step explanation:

Here's a key for end behavior: Look at the leading term

x^even = x -> neg inf, f(x) -> pos inf; x -> pos inf, f(x) -> pos inf

-x^even = x -> neg inf, f(x) -> neg inf; x -> pos inf, f(x) -> neg inf

x^odd = x -> neg inf, f(x) -> neg inf; x -> pos inf, f(x) -> pos inf

-x^odd = x -> neg inf, f(x) -> pos inf; x -> pos inf, f(x) -> neg inf

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What is 6/10 rounded to the nearest half
belka [17]

6/10 rounding to the nearest half would be 1, not 0.

Reason for this: Here is a number line to help you!

|----|----|

Left line = 0

Middle line = 1/2

Right line = 1

Here is another rule!

0/10, 1/10, 2/10, 3/10, 4/10 = rounded to the nearest half would be 0

5/10, 6/10, 7/10, 8/10, 9/10, 10/10 = rounded to the nearest half would be 1.

So 6/10 rounded to the nearest half is 1.

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Xelga [282]
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4 0
3 years ago
Read 2 more answers
If PQ=8 and Q lies at -13 where could P be located?
choli [55]

Answer:

In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).

Step-by-step explanation:

There is really no need to use any quadratics or roots.

( Consider the same problem on the plain number line first.  )

How do you find the number between 2 and 5 which is twice as far from 2 as from 5?

You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get

4=2+23(5−2)

It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then

R=P+23(Q−P)

so in your case we get

R=(0,−1)+23(3,3)=(2,1)

Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)

Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get

s=a+b=2b+b=3b

⇔b=13s⇒a=23s

7 0
3 years ago
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