The molal concentration of the solution is 0.67 mol/kg.
The formula for molal concentration (<em>b</em>) is
<em>b</em> = moles of solute/kilograms of solvent.
Moles of solute = 8.0 g × (1 mol/24 g) = 0.333 mol
b = 0.333 mol/0.50 kg = 0.67 mol/kg
Decomposition,because 1 breaks down into 2
Answer:
6.3 × 10²⁵ atoms of O
Explanation:
Thus, 9.4 mol of C₁₂H₂₂O₁₁ contains 6.3 × 10²⁵ atoms of O.
You would need to isolate the variable by dividing each side by factors that don't contain the variable. So, the answer would be
x = 2.2