Answer:
Explanation:
Hello,
In this case, we can compute the energy by using the following formula for air:
Whereas the moles of air are computed via the ideal gas equation at room temperature inside the 5.5m x 6.5m x 3.0m-room:
Now, we are able to compute heat, by considering that the temperature raise is given in degree Celsius or Kelvins as well:
Finally, we compute the time required for the heating by considering the heating rate and the required heat, shown below:
Regards.
<span>density is how much matter is packed into one area. so the higher density the more likely it is to be heavier. for example, cork has a very low density and iron has a higher density.</span>
<span>Kc = [H2S]²*[O2]³ / [H2O]²*[SO2]²
Let x be the moles of H2S formed. Each mole of H2S takes one each mole of H2O and SO2 so after the reactions
[H2O] = 2.8 - x and [SO2] = 2.6 - x also for each mole of H2S, 1.5 moles of O2 are formed, so [O2] = 1.5*x
Kc = x²*(1.5*x)³ / (2.8 - x)²*(2.6 - x)²
Thus use 2.8 - x = 2.8 and 2.6 - x = 2.6 in the above equation for Kc:
Kc = x²*(1.5*x)³ / 2.8²*2.6² = 3.375x^5 / 2.8²*2.6² = 0.06368*x^5
x^5 = 1.3*10^-6 / 0.06368 = 2.0414*10^-5
x = 0.115M </span>
hope it helps
