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3 years ago

Which particles that make up an atom are involved in nuclear reactions?

Chemistry

2 answers:

gavmur [86]3 years ago

6 0

The particles that make up an atom AND are involved in nuclear reactions are PROTONS AND NEUTRONS.

elena-s [515]3 years ago

3 0

Your answer is going to be B) Protons & neutrons

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If 2.0×10−4 moles of S2O2−8 in 170 mL of solution is consumed in 170 seconds , what is the rate of consumption of S2O2−8?

Ostrovityanka [42]

Answer : The rate of consumption of $S_2O_2^{-8}$ is, $7.0\times 10^{-6}M/s$

Explanation : Given,

Moles of $S_2O_2^{-8}$ = $2.0\times 10^{-4}mol$

Volume of solution = 170 mL = 0.170 L (1 L = 1000 mL)

Time = 170 s

First we have to calculate the concentration.

$\text{Concentration}=\frac{\text{Moles}}{\text{Volume of solution}}$

$\text{Concentration}=\frac{2.0\times 10^{-4}mol}{0.170L}$

$\text{Concentration}=1.2\times 10^{-3}M$

Now we have to calculate the rate of consumption.

$\text{Rate of consumption}=\frac{\text{Concentration}}{\text{Time}}$

$\text{Rate of consumption}=\frac{1.2\times 10^{-3}M}{170s}$

$\text{Rate of consumption}=7.0\times 10^{-6}M/s$

Thus, the rate of consumption of $S_2O_2^{-8}$ is, $7.0\times 10^{-6}M/s$

8 0

3 years ago

Compared to 1 liter aqueous solution with a ph of 7, a 1 liter aqueous solution with a ph of 5.0 contains

Annette [7]

Each unit of pH represents a change by a factor of 10. Thus in a pH of 5, there would be 100x the concentration of Hydrogen ions in solution.

The correct option would be 2.

6 0

3 years ago

Which is a property of a base? (Chemistry test need help please)

OleMash [197]

The answer is C . Watery feel

5 0

3 years ago

(2.25g) x(36.45 g/mol) =___mol HCI

iren2701 [21]

82.0125 just multiply

6 0

3 years ago

The volume of a sample of oxygen is 200.0 mL when the pressure is 3.000 atm and the temperature is 37.0 oC. What is the new temp

attashe74 [19]

Answer:

Explanation:

Given:

V1 = 200 ml

T1 = 20 °C

= 20 + 273

= 293 K

P1 = 3 atm

P2 = 2 atm

V2 = 400 ml

Using ideal gas equation,

P1 × V1/T1 = P2 × V2/T2

T2 = (2 × 400 × 293)/200 × 3

= 234400/600

= 390.67 K

= 390.67 - 273

= 117.67 °C

7 0

3 years ago