How do you find the volume of a prison

Tiwa spent 1 1/2 hours setting up her computer. It took her 3 times as long to install the software. How long did it take Tiwa t

MrRissso [65]

Answer:

Total time spent by Tiwa to set up the computer and install software = 6 hours

Step-by-step explanation:

Given:

Time spent by Tiwa to set up her computer = $1\frac{1}{2}\ hours$

Time spent to install the software is 3 times the time she took to set up the computer.

To find the total time Tiwa took to set up her computer and install the software.

Solution:

Time spent by Tiwa to install the software can be given as:

⇒ $3\times 1\frac{1}{2} \ hours$

<em>In order to multiply mixed numbers we first change them to fractions.</em>

We multiply the denominator to the whole number and add the numerator to it. Then we write the number as numerator of a fraction with the same denominator.

So, $1\frac{1}{2}=\frac{3}{2}$

So, we have:

⇒ $3\times \frac{3}{2}\ hours$

⇒ $\frac{9}{2}\ hours$

Total time spent by Tiwa to set up the computer and install software can be given as:

⇒ $\frac{3}{2}\ hours+\frac{9}{2}\ hours$

Since denominators are same, so we simply add the numerators.

⇒ $\frac{3+9}{2}\ hours$

⇒ $\frac{12}{2}\ hours$

⇒ $6\ hours$

4 0

3 years ago

List the two factor pairs of 10

Triss [41]

The factors of 10 are 1, 2, 5, and 10. You can also look at this the other way around: if you can multiply two whole numbers to create a third number, those two numbers are factors of the third. 2 x 5 = 10, so 2 and 5 are factors of 10. 1 x 10 = 10, so 1 and 10 are also factors of 10.

3 0

3 years ago

(Law of Sines)

Mariana [72]

Answer:

Option (D) is correct.

Step-by-step explanation:

In a triangle BCD , with b, c, d as the sides of triangle.

Sine rule states when we we divide side b by the sine of angle B then it is equal to side c divided by the sine of angle C and also equal to side d divided by the sine of angle D.

Using Sine rule,

$\frac{b}{\sin B}=\frac{c}{\sin C}=\frac{d}{\sin D}$

Consider the first and third ratio,

$\frac{b}{\sin B}=\frac{d}{\sin D}$

Substitute the values of d = 3 , b= 5 and ∠D=25°

$\Rightarrow \frac{5}{\sin B}=\frac{3}{\sin 25^{\circ}}$

$\Rightarrow \sin B=\frac{\sin 25^{\circ} \times 5}{3}}$

$\Rightarrow \sin B=45,135$

Thus, Measure of angle B is 45 and 135 as sinB is positive is first and 2nd quadrant.

Thus, option (D) is correct.

7 0

3 years ago

Read 2 more answers

What is the value of 7-3+(6-2•4)

defon

Answer:

2

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

I arrive at a bus stop at a time that is normally distributed with mean 08:00 and SD 2 minutes. My bus arrives at the stop at an

Nimfa-mama [501]

Answer:

0.0485 = 4.85% probability that you miss the bus.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

When two normal distributions are subtracted, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

In this question:

We have to find the distribution for the difference in times between when you arrive and when the bus arrives.

You arrive at 8, so we consider the mean 0. The bus arrives at 8:05, 5 minutes later, so we consider mean 5. This means that the mean is:

$\mu = 0 - 5 = -5$

The standard deviation of your arrival time is of 2 minutes, while for the bus it is 3. So

$\sigma = \sqrt{2^2 + 3^2} = \sqrt{13}$

The bus remains at the stop for 1 minute and then leaves. What is the chance that I miss the bus?

You will miss the bus if the difference is larger than 1. So this probability is 1 subtracted by the pvalue of Z when X = 1.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1 - (-5)}{\sqrt{13}}$

$Z = \frac{6}{\sqrt{13}}$

$Z = 1.66$

$Z = 1.66$ has a pvalue of 0.9515

1 - 0.9515 = 0.0485

0.0485 = 4.85% probability that you miss the bus.

5 0

3 years ago