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Sergeeva-Olga [200]
3 years ago
10

SCIENCE HELP PLEASE ASAP

Chemistry
1 answer:
likoan [24]3 years ago
4 0

Answer:

atomic number: 42

chemical symbol: mo

number of protons:42

number of electrons:42

atomic mass 96

Explanation:

you got the answers right.

just read what it says

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What mass of sugar and water is needed to make 40 g of 10% solution?​
Iteru [2.4K]

Answer

16g

Percent by mass=  mass of solute/mass of solution * 100

Explanation: work out the equation

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2 years ago
Need help quick! 10 points for correct answer :)
ra1l [238]

Answer:

gram to mole conversation

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3 years ago
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13. What is the frequency of a wave that has a wavelength of 2.73 x 10-7m?​
ella [17]

Answer:

f = 1.09 × 10¹⁵ Hz

Explanation:

Given data:

Frequency of wave = ?

Wavelength of wave = 2.73 ×10⁻⁷ m

Solution:

Formula:

Speed of light = frequency × wavelength

speed of light = 3× 10⁸ m/s

by putting values,

3× 10⁸ m/s = f × 2.73 ×10⁻⁷ m

f = 3× 10⁸ m/s  / 2.73 ×10⁻⁷ m

f = 1.09 × 10¹⁵s⁻¹

s⁻¹ = Hz

f = 1.09 × 10¹⁵ Hz

4 0
3 years ago
PLEASE I'M OFFERING 20 POINTS AND WILL MARK BRAINLIEST. Think about how the geologic time scale was created and how it is divide
xxTIMURxx [149]

Answer:

The geologist time scale was formed when scientists studied rock layers and index fossils worldwide. With this information, they placed Earth's rocks in order by relative age. Later, radioactive dating helped determine the exact age of the divisons in the geologic time scale.

This scale is organized by the 4.6 billion years of earth's history into sections based on important changes seen in the geologic record. The largest intervals are called eons, with each eon containing many millions of years.

In precambarian time the processes that affect Earth's surface have lessened the erosion on the surface. Earth was being hit by meteorites every second. Now there is water erosion and there wasn't back then. The surface changes have lessened over time.

4 0
3 years ago
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A chemist studies the reaction below. 2NO(g) + Cl2(g) 2NOCl(g) He performs three experiments using different concentrations and
Dmitry_Shevchenko [17]

Answer:

1. Rate =k [NO]^{2}[Cl_{2}]

2. k= 0.42 \frac{L^{2}}{mol^{2}*s}

Explanation:

Rate =k [NO]^{m}[Cl_{2}]^{n}

Rate1 = k[0.4]^{m}[0.3]^{n}=0.02\\Rate 2=k [0.8]^{m}[0.3}]^{n}=0.08\\\\\frac{Rate1}{Rate2}=\frac{0.02}{0.08} =\frac{k[0.4]^{m}[0.3]^{n}}{k[0.8]^{m}[0.3]^n}} \\\\\frac{1}{4} =(\frac{1}{2} )^{m},\\m=2

Rate3 =k [0.8]^{m}[0.6]^{n}=0.16\\Rate 2= k[0.8]^{m}[0.3}]^{n}=0.08\\\\\frac{Rate3}{Rate2}=\frac{0.16}{0.08} =\frac{k[0.8]^{m}[0.6]^{n}}{k[0.8]^{m}[0.3]^n}} \\\\\frac{2}{1} =(\frac{2}{1} )^{n},\\n=1

Rate =k [NO]^{2}[Cl_{2}]^{1}

Rate =k [NO]^{2}[Cl_{2}]^{1}\\Rate 1=k [0.4]^{2}[0.3]^{1} =0.02\\k*0.16*0.3=0.02\\k=\frac{0.02}{0.16*0.3}=\frac{1}{8*(\frac{3}{10} )}=\frac{5}{12}  = 0.42 \frac{L^{2}}{mol^{2}*s}

6 0
2 years ago
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