All categories

3 years ago

Balance the following chemical equations

Chemistry

1 answer:

nexus9112 [7]3 years ago

6 0

Explanation:

2Na + I₂ → 2NaI
2KClO₃ → 2KCl + 3O₂
K₃PO₄ + 3HCl → 3KCl + H₃PO₄

You might be interested in

The hardness of water (hardness count )is usually expressed in parts per million(by Mass) CaCO3, which is equivalent to milligra

Ksju [112]

Answer:

1.75 × 10⁻³ M

Explanation:

Given:

Hardness = 175 mg CaCO₃/L

or mass of CaCO₃ in 1 L = 175 × 10⁻³ grams

Now,

Molar mass of CaCO₃ = 40 + 12 + ( 3 × 12 ) = 100 grams/mol

The concentration of CaCO₃ = number of moles / volume

= (175 × 10⁻³ / 100) / 1

= 1.75 × 10⁻³ M

Now,

CaCO₃ ⇒ Ca²⁺ + CO₃²⁻

1.75 × 10⁻³ M 1.75 × 10⁻³ M 1.75 × 10⁻³ M

thus,

the concentration of Ca²⁺ ions in water = 1.75 × 10⁻³ M

4 0

3 years ago

Advantages and disadvantages of chemical

Anit [1.1K]

Answer:

Advantages :they are used for seeing chemical reactions .

they are used for doing chemical experiment .

they are used for making affective medicines .

Disadvantages :they harms to our environment.

they can make side effects in our body by affective medicines made by chemicals.

while doing different unknown experiments they make explosions which can also harm to us.

6 0

3 years ago

Anthony made a pitfall trap by burying a small glass in the ground so that the top of the glass was exactly level with the groun

torisob [31]

Answer:

Spiders and ground beetles.

Why is Anthony so mean? Don't hurt the beetles!

4 0

3 years ago

Balancing equations

Bad White [126]

Make sure you numbers with variable are on one side and the numbers

7 0

4 years ago

Check all that apply.

White raven [17]

Answer:

4 for C in CH4

+4 for C in CO2

-2 for O in all substances

+1 for H in both CH4 and H2O

option 1,2,3 and 4 are correct. Option 5 is not correct

Explanation:

Step 1: Data given

Oxidation number of H = +1

Oxidation number of O = -2

Step 2: The balanced equation

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Step 3: The oxidation numbers

-4 for C in CH4

⇒ Oxidation number of H = +1

⇒ 4x +1 = +4

C has an oxidation number of -4

This is correct.

+4 for C in CO2

⇒ Oxidation number of O = -2

⇒ 2x -2 = -4

C has an oxidation number of +4

This is correct.

-2 for O in all substances

⇒ this is correct, the oxidation number of O is always -2 (except in H2O2 and Na2O2)

This is correct.

+1 for H in both CH4 and H2O

⇒ this is correct, the oxidation number of H is always +1 (except in metal hydrides).

This is correct.

+4 for O in H2O

⇒ Oxidation number of H = +1

⇒ 2x +1 = +2

The oxidation number of O is -2

This is not correct

5 0

3 years ago