Answer:
This happens because there was an electric charge.
Answer:
1. 389 kJ; 2. 7.5 µg; 3. 6.25 days
Explanation:
1. Energy required
The water is converted directly from a solid to a gas (sublimation).
They don't give us the enthalpy of sublimation, but

The equation for the process is then
Mᵣ: 18.02
46.69 kJ + H₂O(s) ⟶ H₂O(g)
m/g: 150
(a) Moles of water

(b) Heat removed
46.69 kJ will remove 1 mol of ice.

2. Mass of water vapour in the freezer
For this calculation, we can use the Ideal Gas Law — pV = nRT
(a) Moles of water
Data:

V = 5 L
T = (-80 + 273.15) K = 193.15 K
Calculation:

(b) Mass of water

3. Time for removal
You must remove 150 mL of water.
It takes 1 h to remove 1 mL of water.

Answer:
how can I solve this ?4Al+3O2 produce 2Al2O3 find a) oxygen atoms needed to react with 5.4 g of aluminium b) grams of oxygen needed to react with 0.6 mol of aluminium?
(A) n=m/M,
n(Al)=5.4/27=0.2 moles
n(O2)=n(Al)*3/4=0.2*3/4=0.15 moles
Number of oxygen atoms= n(O2)*Avogadro's number
=0.15*6.02*10^23=9.03*10^22 oxgyen atoms
(B)
n=m/M
n(Al)=0.6/27=0.02222 moles
n(O2)=n(Al)*3/4=0.016666 moles
m=n*M
m(O2)=0.0166666*32=0.53333 grams
A:The half-life should be similar to the age of the object.
Explanation:
Hopefully this helps!