Iridium-192 is used in cancer treatment, a small cylindrical piece of 192 Ir, 0.6 mm in diameter (0.3mm radius) and 3.5 mm long, is surgically inserted into the tumor. if the density of iridium is 22.42 g/cm3, how many iridium atoms are present in the sample?
Let us start by computing for the volume of the cylinder. V = π(r^2)*h where r and h are the radius and height of the cylinder, respectively. Let's convert all given dimensions to cm first. Radius = 0.03 cm, height is 0.35cm long.
V = π * (0.03cm)^2 * 0.35 cm = 9.896*10^-4 cm^3
Now we have the volume of 192-Ir, let's use the density provided to get it's mass, and once we have the mass let's use the molar mass to get the amount of moles. After getting the amount of moles, we use Avogadro's number to convert moles into number of atoms. See the calculation below and see if all units "cancel":
9.896*10^-4 cm^3 * (22.42 g/cm3) * (1 mole / 191.963 g) * (6.022x10^23 atoms /mole)
= 6.96 x 10^19 atoms of Ir-122 are present.
Answer:
The structure is shown in the figure.
Explanation:
There is condensation polymersiation in case of lactic acid with the removal of water molecule (dehydration) leading to formation of poly lactic acid.
The structure of PLA is shown in the figure.
Answer:
(NH₄)₂(SO₄)+H₂O⇒(NH₄)₂O+H₂(SO₄)
Explanation:
(NH₄)⁺(SO₄)²⁻+H₂O⇒(NH₄)⁺O²⁻+H₂(SO₄)²⁻
(NH₄)₂(SO₄)+H₂O⇒(NH₄)₂O+H₂(SO₄)
Hey I don’t know the answers but try to use the app Socratic or photomath
