1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lukranit [14]
3 years ago
13

Plz someone help me with this

Chemistry
1 answer:
scoray [572]3 years ago
5 0
I would say B but that may not be correct, as I didn't do a full calculation
You might be interested in
Ok another chemistry question! This is another question that I can)t solve
steposvetlana [31]

Hey there!

NaHCO₃

Notice that there is no subscript under Na.

That means there is one atom of Na for each molecule of NaHCO₃.

Hope this helps!

5 0
4 years ago
Match each statements with the state of matter it describes?
Len [333]

Answer:

Solid  liquids , plasma gas

Explanation:

It retains its shape regardless of the shape of the container

5 0
3 years ago
. A bright violet line occurs at 435.8 nm in the emission spectrum of mercury vapor. What amount of energy, in joules, must be r
Tom [10]

Answer :  The energy released by an electron in a mercury atom to produce a photon of this light must be, 4.56\times 10^{-19}J

Explanation : Given,

Wavelength = 435.8nm=435.8\times 10^{-9}m

conversion used : 1nm=10^{-9}m

Formula used :

E=h\times \nu

As, \nu=\frac{c}{\lambda}

So, E=h\times \frac{c}{\lambda}

where,

\nu = frequency

h = Planck's constant = 6.626\times 10^{-34}Js

\lambda = wavelength = 435.8\times 10^{-9}m

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

E=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{(435.8\times 10^{-9}m)}

E=4.56\times 10^{-19}J

Therefore, the energy released by an electron in a mercury atom to produce a photon of this light must be, 4.56\times 10^{-19}J

3 0
4 years ago
If you don't keep giving a car gas, the car will eventually stop. *
Strike441 [17]

Answer:

newtons 2nd law is the answer

3 0
3 years ago
Which Carbon is the triple bound attached to in 6-ethyl-2-octyne?
soldi70 [24.7K]

Answer:

-second

Explanation:

6-ethyl-2-octyne is an unsaturated compound with a triple bond.

6-ethyl-2-octyne will have a triple bound attached to the second carbon. The suffix -yne suggests that compound carry a triple bond and the number  "2" before suffix refers to the position of triple bond that is second carbon.

Hence, the correct option is  "-second ".

7 0
3 years ago
Other questions:
  • The following thermochemical equation is for the reaction of sodium(s) with water(l) to form sodium hydroxide(aq) and hydrogen(g
    14·1 answer
  • What are the three components of every titration?
    6·1 answer
  • What are the indications/signs that a chemical change has occurred?
    6·1 answer
  • If one liquid has a higher volatility than another, and both liquids are at the same
    15·1 answer
  • Determine the number of carbon atoms in 1.00 kg of carbon dioxide.
    7·1 answer
  • Help me answer the question please I don’t get it this is earth science not chemistry.
    5·1 answer
  • What is the distance if traveling 6.5 m/s for 25 seconds
    10·1 answer
  • Chemicals (and humans) are all about what
    14·2 answers
  • Od<br> HXO(s)<br> HX(s)<br> O2 (g)<br> Balanced Ratio?
    9·1 answer
  • 5 ml of 2 normal naoh solution is to be completely neutralized by 100 ml of unknown concentration of h2so4 solution find the mas
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!