First let us find the length of JN
JN =JK +KN
JN = 82+105 = 187
JN=187..............(1)
UC= JN -( JH +HU+CN)
We are given :
JH= 22, HU = 96 and CN = 51
plugging all the values we get
UC = 187-( 22+96+51)
UC =187 -169
UC = 18
Answer is UC =18 ( option B)
[(21 + 5) ÷ 2] + 7 × (8 - 3)
[26 ÷ 2] + 7 × (8 - 3)
13 + 7 × (8 - 3)
13 + 7 × 5
13 + 35
48
start with the ones and every time it goes over ten take the first number and add it to the tens for example 1+8+4+8=21 take the one and put it in the one spot below. Then take the 2 and add it to the six in the tens spot so it would be Instead of 6+8+3+2 it would be 8+8+3+2 which would equal 21 then put the 1 u=in the ten spot below add the 2 to the hundreds spot making is 5+5+7=4=14 put the 4 Below and add the 1 the the thousands making it 3+4+5+1=13 put the one on the ten thousands and put the three below the whole problem would be 13,411.
2 tons is the most reasonable answer
Answer:
180
Step-by-step explanation:
