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bixtya [17]
3 years ago
11

True or false? to find the area of a sector, you multiply the area of the circle by the fraction of the circle covered by that s

ector.
a.true
Mathematics
2 answers:
Wittaler [7]3 years ago
4 0

Answer:

ITs true

Step-by-step explanation:

just did the test

Dmitriy789 [7]3 years ago
3 0
<h2>Answer:</h2>

True

<h2>Step-by-step explanation:</h2>

The area of a sector can be found in two ways:

First. With a formula in degrees.

A=\frac{\pi r^2 \alpha^{\circ}}{360^{\circ}}

Second. With a formula in radians.

A=\frac{r^2 \beta }{2}

For example, for a sector α = 180° (β = π). we have:

A=\frac{\pi r^2 \alpha^{\circ}}{360^{\circ}} \therefore A=\frac{\pi r^2 180^{\circ}} {360^{\circ}} \therefore A=\frac{\pi r^2}{2}\\ \\ \\ A=\frac{r^2 \beta }{2} \therefore A=\frac{r^2 \pi }{2} \therefore A=\frac{\pi r^2}{2}

As you can see, from the two forms we have found out that if you want to find the area of a sector, you multiply the area of the circle by the fraction of the circle covered by that sector, because 180° (π) represents half a circle.

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MA_775_DIABLO [31]

Answer:

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3 years ago
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nikitadnepr [17]

ANSWER : 9 over 4

or 2 and 1/4

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

*3 over 2 x 3 over 2 is 3/2 x 3/2* << this is for me to remember

Okay so multiplying fractions means for us to multiply across. That means if we line the fractions, we multiply. Like this

 3     x     3

-----         -----                3 times 3 is = 9

 2     x     2                  2 times 2 is = 4

9 over 4 is the same thing as 2 and 1/4  << FRACTION    

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2 years ago
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Arada [10]

Answer:

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6 0
2 years ago
PLEASE HELP!!
PSYCHO15rus [73]

<u><em>Answer:</em></u>

The bird is approximately 9 ft high up in the tree

<u><em>Explanation:</em></u>

The required diagram is shown in the attached image

Note that the tree, the cat and the ground form a right-angled triangle

<u>Therefore, we can apply special trigonometric functions</u>

<u>These functions are as follows:</u>

sin(\alpha)=\frac{opposite}{hypotenuse} \\ \\ cos(\alpha)=\frac{adjacent}{hypotenuse} \\ \\tan(\alpha)=\frac{opposite}{adjacent}

<u>Now, taking a look at our diagram, we can note the following:</u>

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<u>This is done as follows:</u>

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5 0
3 years ago
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