The budget is $44000
Total spent so far is $10000 + $8500 = $18500
The amount left to spend = 44000 - 18500 = $25500
$25500 is the maximum 6% commission that Lastima Nelson Inc. can spend and stays within the budget
Let the maximum price of the home be
![x](https://tex.z-dn.net/?f=x)
This value of
![x](https://tex.z-dn.net/?f=x)
will be the 100% before the 6% commission is calculated of it.
6% of
![x](https://tex.z-dn.net/?f=x)
is 25500
1% of
![x](https://tex.z-dn.net/?f=x)
is 25500 ÷ 6 = $4250
100% of
![x](https://tex.z-dn.net/?f=x)
is 4250 × 100 = $425,000
So, the maximum value of the home is $425,000
Answer:
1/4
Step-by-step explanation:
Answer:
x < 4
OR
x > - 2.25
= 4 > x > - 2.25
Step-by-step explanation:
5x - 19 < 1
5x < 1 + 19
5x < 20
x < 20/5
x < 4
OR
- 4x + 3 < - 6
- 4x < - 6 - 3
- 4x < - 9
x > 9/- 4
x > - 2.25
<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units
<u>Solution-</u>
As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with
x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)
Then, substituting these values in the plane equation to get the z parameter,
cos t + 2sin t + z = 2
⇒ z = 2 - cos t - 2sin t
∴ ![\frac{dx}{dt} = -\sin t](https://tex.z-dn.net/?f=%5Cfrac%7Bdx%7D%7Bdt%7D%20%3D%20-%5Csin%20t)
![\frac{dy}{dt} = 2 \cos t](https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdt%7D%20%3D%202%20%5Ccos%20t)
![\frac{dz}{dt} = \sin t-2cos t](https://tex.z-dn.net/?f=%5Cfrac%7Bdz%7D%7Bdt%7D%20%3D%20%5Csin%20t-2cos%20t)
As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π
∴ Arc length
![= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}](https://tex.z-dn.net/?f=%3D%20%5Cint_%7B0%7D%5E%7B2%5Cpi%7D%5Csqrt%7B%28%5Cfrac%7Bdx%7D%7Bdt%7D%29%5E%7B2%7D%2B%28%5Cfrac%7Bdy%7D%7Bdt%7D%29%5E%7B2%7D%2B%28%5Cfrac%7Bdz%7D%7Bdt%7D%29%5E%7B2%7D)
![=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}](https://tex.z-dn.net/?f=%3D%5Cint_%7B0%7D%5E%7B2%5Cpi%7D%5Csqrt%7B%28-%5Csin%20t%29%5E%7B2%7D%2B%282%5Ccos%20t%29%5E%7B2%7D%2B%28%5Csin%20t-2%5Ccos%20t%29%5E%7B2%7D)
![=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)](https://tex.z-dn.net/?f=%3D%5Cint_%7B0%7D%5E%7B2%5Cpi%7D%5Csqrt%7B%282%5Csin%20t%29%5E%7B2%7D%2B%288%5Ccos%20t%29%5E%7B2%7D-%284%5Csin%20t%5Ccos%20t%29)
Now evaluating the integral using calculator,
![= 13.5191](https://tex.z-dn.net/?f=%3D%2013.5191)
Answer:
(a) seems to be the closest to being correct of these five statements.
Step-by-step explanation:
Let's go through the list of possible descriptors:
a) There are no outliers. This seems to be the response most likely to be correct.
b) The distribution is not skewed left. It's skewed right.
c) The center is not 44. From what I see, the center is 48.
d) This distribution is not bimodal; it does not have two peaks.
d) The spread is not 38 to 67; it's 29 to 67.