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cricket20 [7]
3 years ago
13

A candy maker mixed marshmallows worth $1.80 a pound with rice crisipes worth $3.20 a pound to make 50 pounds of a rice crispie

treats worth $2.92 a pound. Find the number of pounds of each item used.
Mathematics
1 answer:
Orlov [11]3 years ago
4 0
\bf \begin{array}{lccclll}
&amount&price&\textit{price per amount}\\
&-----&-----&--------\\
\textit{marshmallows}&x&1.80&(1.80)(x)\\
\textit{rice crispies}&y&3.20&(3.20)(y)\\
-----&-----&-----&--------\\
mixture&50&2.92&(50)(2.92)
\end{array}\\\\
-----------------------------\\\\

\begin{cases}
x+y=50\implies \boxed{y}=50-x\\
1.80x+3.20y=(50)(2.92)\\
----------\\
1.80x+3.20\left( \boxed{50-x} \right)=(50)(2.92)
\end{cases}

solve for "x", to see how many lbs of marshmallows were needed

what about "y"?   well, y = 50 - x
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200 m.

Step-by-step explanation:

Step 1:

Length × Width = Area      Equation

Step 2:

5 × 40      Multiply

Answer:

Area = 200

Hope This Helps :)

8 0
3 years ago
Identify the solution set of the given inequality using the given replacement set.   x > –4; {–8, –4.3, –4 –3.8, 1.2, 3}  
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<span>x> -4 means that it is needed to find all the values that are greater than -4 "not including" -4 ... for negative values as you get from zero the values decrease which means that -8 is less than -7 and -7 is less than -6 etc.. and positive values are trivially known to be greater than negative ones then take each value and compare it with -4 -8 is less than -4 -4.3 is less than -4 -4 is equal to -4 which is not included in our required range which is x>-4 -3.8 is greater than -4 which will get in our solution 1.2 is greater than -4 3 is also greater than -4 So our final solution will be {-3.8,1.2,3} Which is B in our question Hope this helps :) Let me know too if you got it :) </span><span>
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3 0
3 years ago
5<br> 1<br> The measure of Z1 =<br> O 55<br> O62.5<br> 110<br> 5
Akimi4 [234]

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Step-by-step explanation:

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So, by the inscribed angle theorem, angle 1 measures 55 degrees.

5 0
2 years ago
The following data represent the monthly phone use, in minutes, of a customer enrolled in a fraud prevention program for the pas
Illusion [34]

Answer:

The answer is "717.25 minutes".

Step-by-step explanation:

In this question first, we arrange the value in ascending order that are:

307,311,321,322,354,363,377,406,425,435,461,464,474,499,505,513,517,534,548

The median is always in an orderly position that is = \frac{(n+1)}{2}.

\to \frac{(n+1)}{2} = \frac{(20+1)}{2} = 10.5  position orders

10^{th} \ and \ 11^{th} place an average of observations so, the

Average = \frac{(425 +435)}{2} = \frac{(860)}{2} =430

Because as medium stands at 10.5 that median is as below 10 are greater than the level.

Q_1 often falls throughout the ordered BELOW average is = \frac{(n+1)}{2} place.

\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}ordered position

Average 5^{th} \ and \ 6^{th}  location findings

Q_1 = \frac{(354+363)}{2} = \frac{(717)}{2}= 358.5

In  = \frac{(n+1)}{2} the ordered place, Q3 always falls ABOVE the median.

\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th} ordered At median ABOVE 

Consequently Q_3 falls between 5^{th} \ and \ 6^{th} ABOVE the median position

15^{th}\  and \ 16^{th}place average of observations

\to Q_3 = \frac{(499+505)}{2}=\frac{(1004)}{2}  = 502

\to IQR = Q_3 - Q_1= 502-358.5= 143.5  

\to \text{Upper fence} = Q_3 + 1.5 \times IQR= 502 + 1.5 \times 143.5 = 717.25

4 0
3 years ago
What is the product of (p3)(2p2 - 4p)(3p2 - 1)?
Evgen [1.6K]

2p5-4p3(3p2-1)

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6p7-14p5+4p3

8 0
4 years ago
Read 2 more answers
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