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KATRIN_1 [288]
3 years ago
5

Find the sum 5,-7 a. 2 b. -2 c. -35 d. 12

Mathematics
1 answer:
Irina-Kira [14]3 years ago
5 0

It would be, 5+(-7) = 5-7 = -2

B)Option B is your answer........


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Find the Volume. help please ​
Oksana_A [137]
104 1/2ft cubed
To find the volume you would multiply
Length•width•height
So,
(6 1/3)(3)(5 1/2)=104 1/2
So it would be 104 and 1/2 or 104.5
6 0
2 years ago
How do I find x on the attached right triangle<br> ?
ioda

The value of x from the given triangle is 32√3/3

<h3>SOH CAH TOA identity</h3>

In order to determine the value of x, first we need to determine the hypotenuse side of the smaller triangle.

sin 60 = 8√2/H

H = 8√2/sin60

H = 8√2 * 2/√3

H = 16√2/√3
H = 16√6/3

For the value of x, we will use the expression

sin45 = (16√6/3)/x

1/√2 = 16√6/3x
3x = 16√12
3x = 32√3

x = 32√3/3

Hence the value of x from the given triangle is 32√3/3

Learn more on SOH CAH TOA here: brainly.com/question/20734777

#SPJ1

4 0
2 years ago
An angle measures 64° more than the measure of a complementary angle. What is the measure of each angle?
GarryVolchara [31]
Complementary angles are 90 degrees,so if the angle is 64 degrees more,you just only have to add 90+64=154.

The measure of the angle is 154 degrees

Hope i helped.

Remember:complimentary angles add up to 90 while supplementary angles add up to 180.
6 0
3 years ago
Whate is answer of 36-[100÷5{60-32(8÷4-1)}]​
svet-max [94.6K]

Answer:

67\frac{23}{28}

Step-by-step explanation:

36-\left[100\div \:560-32\left(8\div \:4-1\right)\right]\\\\100\div \:560-32\left(8\div \:4-1\right)\\\\=100\div \:560-32\cdot \:1\\\\=\frac{100}{560}-32\cdot \:1\\\\=\frac{100}{560}-32\\\\=-\frac{891}{28}\\\\\\=36-\left(-\frac{891}{28}\right)\\\\36-\left(-\frac{891}{28}\right)\\\\=36+\frac{891}{28}\\\\\frac{36\cdot \:28}{28}+\frac{891}{28}\\\\\frac{36\cdot \:28+891}{28}\\\\=\frac{1899}{28}\\\\\\\frac{1899}{28}(1899\div28)=67\frac{23}{28}

6 0
1 year ago
He how do you do this
OlgaM077 [116]

Answer:

I'm not sure. have you tried googling? Also where is comments on this site I'm kinda new

Step-by-step explanation:

4 0
2 years ago
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