Find the sum 5,-7 a. 2 b. -2 c. -35 d. 12

Help me with this plzzzzzzzzz

Darya [45]

Answer:

x=1, y=2

Step-by-step explanation:

5 0

4 years ago

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Alexis has a savings account that earns 2.1% interest compounded daily. If she opened the account 17 years ago with a deposit of

sergejj [24]

Compound Interest Formula: A = P(1 + r/n)^(n·t)

A = final amount r = rate, as a decimal (.021) t = number of years (17)

P = initial amount (2914.72) n = number of times compounded per year (365)

A = 2914.72(1 + .021/365)^(365·17) = $4165.20

Interest earned: $4165.20 - $2914.72 = $1250.48 <----- Answer

You might want to recalculate this, attempting to handle leap years, by replacing the number of times compounded per year with 365.25 and see if that has an effect

5 0

3 years ago

Simplify (4x - 6) + (5x + 1). a)9x + 5 b)9x-5 c)x-5 d)-X-5

Lelechka [254]

Answer:

b

Step-by-step explanation:

just add x values and numbers

6 0

3 years ago

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At NC State University, 16.4% of the undergraduate classes have more than 50 students. If a random sample of 200 undergraduate c

Lena [83]

Answer:

We need to check the conditions in order to use the normal approximation.

$np=200*0.164=32.8 \geq 10$

$n(1-p)=200*(1-0.164)=167.2 \geq 10$

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$p =0.164$

And the deviation is given by:

$\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262$

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=200, p=0.164)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We need to check the conditions in order to use the normal approximation.

$np=200*0.164=32.8 \geq 10$

$n(1-p)=200*(1-0.164)=167.2 \geq 10$

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$p =0.164$

And the deviation is given by:

$\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262$

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

6 0

3 years ago

Joe wants to purchase an electric keyboard. The price of the keyboard at Macelli’s, with tax, is $2,344. He can save $150 per mo

Juli2301 [7.4K]

Answer:

Step-by-step explanation:

abought 16 months to buy it and he will have

56 extra cash hope ihelped :3

7 0

4 years ago

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