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Snowcat [4.5K]
4 years ago
12

Place the graphs in descending order based on their y value as x approaches infinity.

Mathematics
1 answer:
oee [108]4 years ago
5 0

To answer this question, we need to know that as x tends to infinity

the exponential values greatly increase with each passing x.

So the exponential values will always be greater than the linear values, as x increases.

Lets see that with an example

Suppose we have

y1 = 2*x

y2 =  2^x

If we evaluate at x = 5, we can see the difference between the two

y1 = 2*(5) = 10

y2 =  2^(5) = 32

If x = 10, the difference becomes even clearer

y1 = 2*(10) = 20

y2 =  2^(10) = 1024

To order the exponential graphs, we need to place ourselves at an specific value of x and check which graphs has the highest corresponding value of y

So the answer to your question, which is to place in descending order according to the value of y:

*green

*orange

*blue

*red

*yellow

*black

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74% of freshmen entering public high schools in 2006 graduated with their class in 2010. A random sample of 81 freshmen is selec
Assoli18 [71]

Answer: Probability that the proportion of students who graduated is greater than 0.743 is P = 0.4755

Step-by-step explanation:

Given that,

Probability of freshmen entering public high schools in 2006 graduated with their class in 2010, p = 0.74

Random sample of freshman, n = 81

Utilizing central limit theorem,

P(\hat{p}

So,

(P(\hat{p}>0.743) = P(Z>0.743 - \frac{0.74}{\sqrt{\frac{0.74(1-0.74)}{81} }  } )

= P( Z > 0.0616)

= 0.4755 ⇒ probability that the proportion of students who graduated is greater than 0.743.

7 0
3 years ago
Which one is true!!!
irga5000 [103]
B and C I believe .............
7 0
3 years ago
Consider this right triangle.<br> 21<br> 29<br> 20<br> Enter the ratio equivalent to s
AleksAgata [21]

Answer:

Part 1) sin(B)=\frac{21}{29}

Part 2) csc(A)=\frac{29}{20}

Part 3) cot(A)=\frac{21}{20}

Step-by-step explanation:

<u><em>The complete question is</em></u>

Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B

The picture of the question in the attached figure

Part 1) Write the ratio equivalent to: Sin B

we know that

In the right triangle ABC

sin(B)=\frac{AC}{AB} ----> by SOH (opposite side divided by the hypotenuse)

substitute the values

sin(B)=\frac{21}{29}

Part 2) Write the ratio equivalent to: Csc A

we know that

In the right triangle ABC

csc(A)=\frac{1}{sin(A)}

sin(A)=\frac{BC}{AB} -----> by SOH (opposite side divided by the hypotenuse)

substitute the values

sin(A)=\frac{20}{29}

therefore

csc(A)=\frac{29}{20}

Part 3) Write the ratio equivalent to: Cot A

we know that

In the right triangle ABC

cot(A)=\frac{1}{tan(A)}

tan(A)=\frac{BC}{AC} -----> by TOA (opposite side divided by the adjacent side)

substitute the values

tan(A)=\frac{20}{21}

therefore

cot(A)=\frac{21}{20}

4 0
3 years ago
The perimeter of a playing field for a certain sport is 334ft. The field is a rectangle, and the length is 47 ft longer than the
babunello [35]

Answer:

The dimensions of the rectangle = 60ft by 107ft

Where 60 ft = Width of the playing field

107ft = Length of the playing field

Step-by-step explanation:

A playing field is Rectangular is shape, hence,

The formula for Perimeter of a rectangle = 2(L + W)

P = 334 ft

L = 47 + W

W = W

Hence we input these values in the formula and we have:

334 = 2(47 + W + W)

334 = 2(47 + 2W)

334 = 94 + 4W

334 - 94 = 4W

240 = 4W

W = 240/4

W = 60

There fore, the width of this playing field = 60 ft

The length of this rectangle is calculated as:

47 + W

47 + 60

= 107 ft

The length of this playing field = 107ft

Therefore the dimensions of the rectangle = 60ft by 107ft

6 0
3 years ago
9. PART A: Which of the following best summarizes
ivanzaharov [21]

Answer:

D Stanton encourages the audience to spread the word for their cause

Step-by-step explanation:

I just know I have done the test and it makes the most sense. :)

3 0
3 years ago
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