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3 years ago

Please help meh please.

Mathematics

1 answer:

GuDViN [60]3 years ago

8 0

Answer:

d. 84.5

Step-by-step explanation:

You will have to put the numbers in order than cross out one from each side;

70x

80x

88x

In doing this you have taken out B,E, and F. The answer would have to be somewhere in between 83 and 86, which would be around 84 and 85, so therefore the answer would be 84.5

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What is an estimate of 23 times 67
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3 years ago

Convert the measurements 66,597 grams = how many kgs

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Answer

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divide by 1000

66.597 kg

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3 years ago

Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo

natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

P(B) is the probability of the person having cancer, so $P(B) = 0.009$

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So $P(A/B) = 0.91$

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

$P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765$

What is the probability that the person actually does have cancer?

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213$

There is a 12.13% probability that the person actually does have cancer.

3 0

3 years ago

Geometry Special Quadrilaterals show work please

Charra [1.4K]

Answer:

a = 16

w = 125

x = 120

y = 55

Step-by-step explanation:

FINDING 'a'

31 = a + 46 / 2

62 = a + 46

16 = a

FINDING 'w'

* This section looks Non-Isosceles trapezoid so I will be following the rule according it

w + 55 = 180

w = 125

FINDING 'y'

y = 55

- Because of corresponding angles

FINDING 'x'

* In this case it looks like we are still dealing w/ an non-isosceles trapezoid.

x + 60 = 180

x = 120

Hope this helped ^^

(Please inform me of any mistakes or misunderstandings!)

6 0

3 years ago