1/3 a + 2 < -2
1/3a < -4
a < -4*3
a < -12 Answer
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Answer: Choice C) 
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This is a more complicated way to write 
The range is the set of all possible y outputs of a function. So we use the graph to see what y values are possible. The graph shows that y can be anything smaller than y = 2. We can't actually reach y = 2 itself due to a horizontal asymptote here.
In interval notation, the answer would be
with the curved parenthesis to indicate "do not include y = 2 as part of the range".
Answer:
Gila Monster is 1.54 times that of Chuckwalla.
Step-by-step explanation:
Given:
Average Length of Gila Monster = 0.608 m
Average Length of Chuckwalla = 0.395 m
We need to find the number of times the Gila monster is as the Chuckwalla.
Solution:
Now we know that;
To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.
framing in equation form we get;
number of times the Gila monster is as the Chuckwalla = 
Rounding to nearest hundredth's we get;
number of times the Gila monster is as the Chuckwalla = 1.54
Hence Gila Monster is 1.54 times that of Chuckwalla.
Answer:
5.5 servings
Step-by-step explanation:
4+7=11
11/2=5.5 sevings
Answer:
-3x^6 -x^4 +2x^3 -8x +8
Step-by-step explanation:
Use the distributive property 4 times.
(-3x^3 + 2x - 4)×(x^3 + x - 2)
= -3x^3(x^3 +x -2) +2x(x^3 +x -2) -4(x^3 +x -2) . . . . once
= -3x^6 -3x^4 +6x^3 +2x^4 +2x^2 -4x -4x^3 -4x +8 . . . . 3 more times
= -3x^6 +x^4(-3+2) +x^3(6 -4) +2x^2 +x(-4 -4) +8 . . . . group like terms
= -3x^6 -x^4 +2x^3 -8x +8