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Serga [27]
3 years ago
12

What is 9+(-3)=?? Someone please help me

Mathematics
2 answers:
Vitek1552 [10]3 years ago
4 0

Answer is 6.

Get this by:

9+(-3)= ?

When you have the # + -# you will subtract. Hence 9 PLUS a negative 3 you get 6.

pentagon [3]3 years ago
3 0

The answer to 9+(-3)=6

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7 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down,drag into the correct p
boyakko [2]

Answer:

\boxed{\sf \ \ 9x^2-18x-7 \ \  divided \ by \ (3x+1) \ is \ (3x-7) \ }

Step-by-step explanation:

Hello,

let's find a and b reals so that

9x^2-18x-7=(3x+1)(ax+b)

(3x+1)(ax+b)=3ax^2+(3b+a)x+b

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so ti goes with a = 9/3 = 3, b = -7

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9x^2-18x-7=(3x+1)(3x-7)

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8 0
3 years ago
Can someone help me with this
Marizza181 [45]

Answer:

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7 0
2 years ago
Identify some exterior angles in the figure. Select the two correct answers.
Naya [18.7K]
A and C are the correct answers
4 0
2 years ago
2. Consider the circle x^2−4x+y^2+10y+13=0. There are two lines tangent to this circle having a slope of 2/3.
likoan [24]

Answer:

a) The coordinates are (0.431, -2.646) and (3.568,-7.354)

b) The tangent lines are

l₁ = (x-0.431)*2/3 - 2.646

l₂ = (x-3.568)2/3 - 7.354

Step-by-step explanation:

First, lets complete squares, by taking for each cordinate the square of a linear expression

0= x²−4x+y²+10y+13 = (x-2)²+ 4  + (y+5)²-25+13 = (x-2)²+(y+5)² - 8

Hence (x-2)² + (y+5)² = 8

Lets put y in function of x. We should obtain 2 functions f and g that represent the circle.

(y+5)² = 8 - (x-2)² = -x² + 4x + 4

y = ^+_- \sqrt{-x^2+4x+4} -5

Thus

f(x) = \sqrt{-x^2+4x+4} - 5

g(x) = -\sqrt{-x^2+4x+4} - 5

Lets find the derivate of each function and the points in which they reach the value 2/3. In those points the tangent line will have a slope of 2/3.

We may just find the values of x which the derivate of f is either 2/3 or -2/3.

\frac{-x+2}{\sqrt{-x^2+4x+4}} = ^+_-\frac{2}{3} \Leftrightarrow \frac{x^2-4x+4}{-x^2+4x+4} = \frac{4}{9} \Leftrightarrow 9(x^2-4x+4) = 4(-x^2+4x+4) \\\Leftrightarrow 13x^2-52x+20 = 0

The quadratic has roots

\frac{52 ^+_-\sqrt{1664}}{26}

one root is 3.568, which corresponds with g, and the other root is 0.431, corresponding to f.

Also g(3.568) = - 7.354 and f(0.431) = -2.646

This means that the coordinates are (0.431 , -2.646), (3.568 , -7.354) and the tangent lines are

l₁ = (x-0.431)*2/3 - 2.646

l₂ = (x-3.568)2/3 - 7.354

5 0
2 years ago
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