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3 years ago

Find the value of x round to the nearest tenth 11.2 12.6 17.5 35.7

Mathematics

2 answers:

Alinara [238K]3 years ago

7 0

Answer: 11.2

Step-by-step explanation:

Mashcka [7]3 years ago

6 0

Answer: It’s not 17.5 I can tell you that:(( just got it wrong

Step-by-step explanation:

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What is the definition of a ray

Elan Coil [88]

Mathematically, a ray is a portion of a line which starts at a point and goes off in a particular direction to infinity.

4 0

3 years ago

How many hours did I work if I worked 7 hours and 30 minutes a day, for 15 days?

baherus [9]

Answer:

112 hours and 50 mins

Step-by-step explanation:

Numbers of mins worked in a day = 7×60+30 =450 mins

Now number of mins worked in 15 days = 450×15

= 6750 mins

to convert mins into hours divide by 60

6750÷60 = 112.50

that means total number of hours worked in 15 days = 112 hours and 50 mins

8 0

3 years ago

A bowl is in the shape of a hemisphere (half a sphere) with a diameter of 8 inches. Find the volume of the bowl. Use 3.14 for pi

gayaneshka [121]

Answer: 267.947 (or 267.95) inches^3

Step-by-step explanation:

The formula for the volume of a sphere is $\frac{4}{3}\pi r^{3}$ .

To find your radius (r), divide the diameter of 8 inches by 2. The radius is 4 inches.

Plug in your numbers to the volume equation to get $\frac{4}{3} (3.14)(4^3)$ . The first step is to cube 4 (4*4*4) to get 64. Now your equation is $\frac{4}{3}(3.14)(64)$ .

Multiply 3.14 and 64 to get 200.96. The equation is now $\frac{4}{3}(200.96)$ or $\frac{4}{3} * \frac{200.96}{1}$ .

Multiply the numerators (4 * 200.96) and denominators (1 * 3) to get a final equation of $\frac{803.84}{3}$ .

Finally, divide 803.84 by 3 to get the final answer of 267.947 in^3.

8 0

2 years ago

The height h (in feet) of an object dropped from a ledge after x seconds can be modeled by h(x)=−16x2+36 . The object is dropped

kakasveta [241]

Check the picture below.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases}$

so the object hits the ground when h(x) = 0, hmmm how long did it take to hit the ground the first time anyway?

$\bf h(x)=-16x^2+36\implies \stackrel{h(x)}{0}=-16x^2+36\implies 16x^2=36 \\\\\\ x^2=\cfrac{36}{16}\implies x^2 = \cfrac{9}{4}\implies x=\sqrt{\cfrac{9}{4}}\implies x=\cfrac{\sqrt{9}}{\sqrt{4}}\implies x = \cfrac{3}{2}~~\textit{seconds}$

now, we know the 2nd time around it hit the ground, h(x) = 0, but it took less time, it took 0.5 or 1/2 second less, well, the first time it took 3/2, if we subtract 1/2 from it, we get 3/2 - 1/2 = 2/2 = 1, so it took only 1 second this time then, meaning x = 1.

$\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill$

quick info:

in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².

4 0

3 years ago

17. What unit of time will make the statement true? seconds + seconds x day = seconds ?

inna [77]

Answer:

seconds could be anything but day was 0 then there would be no seconds, right??? that would basically be true.

Step-by-step explanation:

8 0

3 years ago