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daser333 [38]
4 years ago
7

Given f(x) = x - 7 and g(x) = x2. Find g(f(4)). 9(4)) =

Mathematics
1 answer:
aivan3 [116]4 years ago
6 0
My work to your question

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Find c and round to the nearest tenth. thank you in advance
PSYCHO15rus [73]

Answer and Step-by-step explanation:

90ft = a

55ft = b

50ft = c

Plug into equation.

50^{2}  = 90^{2}  + 55^{2}  - 2(90)(55)cosC\\\\2500 = 11125 - 9900(cosC)\\\\-8625 = -9900(cosC)\\\\0.8712 = cosC\\\\cos^{-1} (0.8712) = C\\\\29.4

29.4° is the answer.

4 0
3 years ago
9)Rover the dog is on a 60-foot leash. One end of the leash is tied to Rover, who is 2 feet tall. The
Sidana [21]

The dog can roam 59.7 feet if the dog is on a 60-foot leash. One end of the leash is tied to Rover, who is 2 feet tall.

<h3>What is the Pythagoras theorem?</h3>

The square of the hypotenuse in a right-angled triangle is equal to the sum of the squares of the other two sides.

We have:

Rover the dog is on a 60-foot leash. One end of the leash is tied to Rover, who is 2 feet tall. The other end of the leash is tied to the top of an 8-foot pole.

After drawing a right-angle triangle from the above information.

Applying Pythagoras' theorem:

60² = 6² + x²

After solving:

x = 59.69 ≈ 59.7 foot

Thus, the dog can roam 59.7 feet if the dog is on a 60-foot leash. One end of the leash is tied to Rover, who is 2 feet tall.

Learn more about Pythagoras' theorem here:

brainly.com/question/21511305

#SPJ1

5 0
2 years ago
Jeremy has a total of $250. If he spends 30% of his money, how much will he have left?
vagabundo [1.1K]
If you look at the picture, you set it up as part over whole is equal to percent over 100. then you just multiply across.

5 0
4 years ago
Edafjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj
Arturiano [62]

Answer:

fjjjjjjjjjjjjjj?

aefieoapowiejfie

8 0
3 years ago
Find the mass of the triangular region with vertices (0, 0), (3, 0), and (0, 1), with density function ρ(x,y)=x2+y2.
ololo11 [35]

Since density is the ratio of mass to (in this case) area, we can find the mass of the triangular region \mathcal T by computing the double integral of the density function over \mathcal T:

\mathrm{mass}=\displaystyle\iint_{\mathcal T}\rho(x,y)\,\mathrm dx\,\mathrm dy

The boundary of \mathcal T is determined by a set of lines in the x,y plane. One way to describe the region \mathcal T is by the set of points,

\mathcal T=\left\{(x,y)\mid0\le x\le 3\,\land\,0\le y\le1-\dfrac x3\right\}

So the mass is

\mathrm{mass}=\displaystyle\int_{x=0}^{x=3}\int_{y=0}^{y=1-x/3}(x^2+y^2)\,\mathrm dy\,\mathrm dx

=\displaystyle\int_{x=0}^{x=3}\left(x^2y+\frac{y^3}3\right)\bigg|_{y=0}^{y=1-x/3}\,\mathrm dx

=\displaystyle\int_{x=0}^{x=3}\left(x^2\left(1-\frac x3\right)+\frac{\left(1-\frac x3\right)^3}3\right)\,\mathrm dx

=\displaystyle\frac1{81}\int_0^3(27-27x+90x^2-28x^3)\,\mathrm dx=\frac52

6 0
3 years ago
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