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dimulka [17.4K]
3 years ago
11

Factorize (3r-2p)^2 - (3d-2e)^2

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
3 0

⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✿⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✳︎

Hi my lil bunny!

❀ _____.______❀_______._____ ❀

Since both terms are perfect squares, factor using the difference of squares formula, a^2 - b^2 = ( a+ b) ( a-b) where a = 3r - 2p and b = 3d - 2e

_____________________________

So the answer is :  ( 3r - 2p + 3d - 2e ) ( 3r - 2p - 3d - 2e)

❀ _____.______❀_______._____ ❀

Xoxo, , May

⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✿⭐︎✳︎⭐︎✳︎⭐︎✳︎⭐︎✳︎

Hope this helped you.

Could you maybe give brainliest..?

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Answer:

z=0.842

And if we solve for a we got

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

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P(X   (b)

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If we use condition (b) from previous we have this:

P(X  

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But we know which value of z satisfy the previous equation so then we can do this:

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And if we solve for a we got

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nadezda [96]

Answer:

I think your right

hope this helps

have a good day :)

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Read 2 more answers
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