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3 years ago

12

The mean of a normally distributed dataset is 12, and the standard deviation is 2. % of the data points lies between 8 and 16. N

extReset

1 answer:

quester [9]3 years ago

6 0

Appaently the answer is 95.4%

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Plz answer only if you know it's correct. willl give brainliest to best answer

just olya [345]

Answer:

i believe is is 3/2

Step-by-step explanation:

as y goes up 30 x goes over 20

30/20 simplified is 3/2

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3 years ago

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3. The sum of a number of 2 digits and of the number formed by reversing the digits is 110, and the difference of the digits is

VladimirAG [237]

Answer:

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2 years ago

The sales tax on clothing in Louisiana is 4% . Calculate how much tax you need to pay on a dress if it costs $19.50 before befor

SVEN [57.7K]

Answer:

.78 cents

Step-by-step explanation:

To find the tax amount on any number, divide that number by 100 and then multiple it by the tax percentage.

In this case that would look like: $19.50/100 times 4 =.78

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3 years ago

From the top of a tree a bird looks down on a field mouse at an angle of depression of 50 degrees if the field mouse is 40 M fro

Zepler [3.9K]

The tangent function gives the ratio of vertical to horizontal distance in this case.
.. vertical distance = (horizontal distance)*tan(angle of depression)
.. = (40 m)*tan(50°)
.. vertical distance ≈ 47.7 m

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3 years ago

The equation giving a family of ellipsoids is u = (x^2)/(a^2) + (y^2)/(b^2) + (z^2)/(c^2) . Find the unit vector normal to each

Fynjy0 [20]

Answer:

$\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

Step-by-step explanation:

Given equation of ellipsoids,

$u\ =\ \dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2}$

The vector normal to the given equation of ellipsoid will be given by

$\vec{n}\ =\textrm{gradient of u}$

$=\bigtriangledown u$

$=\ (\dfrac{\partial{}}{\partial{x}}\hat{i}+ \dfrac{\partial{}}{\partial{y}}\hat{j}+ \dfrac{\partial{}}{\partial{z}}\hat{k})(\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2})$

$=\ \dfrac{\partial{(\dfrac{x^2}{a^2})}}{\partial{x}}\hat{i}+\dfrac{\partial{(\dfrac{y^2}{b^2})}}{\partial{y}}\hat{j}+\dfrac{\partial{(\dfrac{z^2}{c^2})}}{\partial{z}}\hat{k}$

$=\ \dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}$

Hence, the unit normal vector can be given by,

$\hat{n}\ =\ \dfrac{\vec{n}}{\left|\vec{n}\right|}$

$=\ \dfrac{\dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}}{\sqrt{(\dfrac{2x}{a^2})^2+(\dfrac{2y}{b^2})^2+(\dfrac{2z}{c^2})^2}}$

$=\ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

Hence, the unit vector normal to each point of the given ellipsoid surface is

$\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

3 0

3 years ago