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Otrada [13]
3 years ago
5

What's the scientific notation for 420

Mathematics
2 answers:
LenKa [72]3 years ago
8 0
4.2•10^2 is the answer to your question
fenix001 [56]3 years ago
4 0
The person on top got the correct answer so put his down i was gonna write that
You might be interested in
Please help (Determine the slope of the line. Show the work you did to find the slope.)
Scrat [10]

Answer:

slope of line is 3/5

Step-by-step explanation:

slope is the ratio of the change in the y-values over the change in the x-values

in this problem, if you go from pt A to pt B, you rise by 3 and go to the right by 5, thus slope of 3/5

if you go from pt B to pt C, you rise by 6 and go to the right by 10

however, 6/10 can be reduced to 3/5

if you start at point (0,2) and rise by 3 and run to the right by 5 you are at point (5,5)

change in y-values is 5-2 or 3

change in x-values is 5-0 or 5

(5-2)/(5-0) = 3/5

3 0
3 years ago
Help me !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
ElenaW [278]
So 20% is 1/5 as a percent.

So 1/5 multiplied by 5 equals 5/5, or 1.

So if 1/5 = 6, then 6 multiplied by 5, or 30, must equal 5/5, or 1.

So the total number of dolls in Amyia's doll collection is 30.
7 0
3 years ago
List the like terms of the expression 3n+5p+2+n
IgorC [24]

Answer:only the ones that have letterers *m* are like terms

Step-by-step explanation: for example

5j+9u+3+6n+N

5j 9u 6n n are all like terms

4 0
3 years ago
What happens to the value of the expression 1+3f1+3f1, plus, 3, f as fff increases? Choose 1 answer: Choose 1 answer: (Choice A)
Leto [7]

Answer:

A. It Increases

Step-by-step explanation:

Given the expression:

1+3f

When f=1, 1+3f=1+3(1)=1+3=4

When f=2, 1+3f=1+3(2)=1+6=7

When f=3, 1+3f=1+3(3)=1+9=10

We can see that the value of the given expression for each successive term increases and in fact form the sequence

4,7,10,...

Therefore, when f increases, 1+3f increases.

7 0
3 years ago
Read 2 more answers
Does anybody know how to do time with exponential decay
My name is Ann [436]
<span>From the message you sent me:

when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths

If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

b_n=0.12\times b_{n-1}

Why does this work? Initially, you start with 500 mL of air that you breathe in, so b_1=500\text{ mL}. After the second breath, you have 12% of the original air left in your lungs, or b_2=0.12\timesb_1=0.12\times500=60\text{ mL}. After the third breath, you have b_3=0.12\timesb_2=0.12\times60=7.2\text{ mL}, and so on.

You can find the amount of original air left in your lungs after n breaths by solving for b_n explicitly. This isn't too hard:

b_n=0.12b_{n-1}=0.12(0.12b_{n-2})=0.12^2b_{n-2}=0.12(0.12b_{n-3})=0.12^3b_{n-3}=\cdots

and so on. The pattern is such that you arrive at

b_n=0.12^{n-1}b_1

and so the amount of air remaining after 50 breaths is

b_{50}=0.12^{50-1}b_1=0.12^{49}\times500\approx3.7918\times10^{-43}

which is a very small number close to zero.</span>
5 0
3 years ago
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