Answer:
slope of line is 3/5
Step-by-step explanation:
slope is the ratio of the change in the y-values over the change in the x-values
in this problem, if you go from pt A to pt B, you rise by 3 and go to the right by 5, thus slope of 3/5
if you go from pt B to pt C, you rise by 6 and go to the right by 10
however, 6/10 can be reduced to 3/5
if you start at point (0,2) and rise by 3 and run to the right by 5 you are at point (5,5)
change in y-values is 5-2 or 3
change in x-values is 5-0 or 5
(5-2)/(5-0) = 3/5
So 20% is 1/5 as a percent.
So 1/5 multiplied by 5 equals 5/5, or 1.
So if 1/5 = 6, then 6 multiplied by 5, or 30, must equal 5/5, or 1.
So the total number of dolls in Amyia's doll collection is 30.
Answer:only the ones that have letterers *m* are like terms
Step-by-step explanation: for example
5j+9u+3+6n+N
5j 9u 6n n are all like terms
Answer:
A. It Increases
Step-by-step explanation:
Given the expression:
1+3f
When f=1, 1+3f=1+3(1)=1+3=4
When f=2, 1+3f=1+3(2)=1+6=7
When f=3, 1+3f=1+3(3)=1+9=10
We can see that the value of the given expression for each successive term increases and in fact form the sequence
4,7,10,...
Therefore, when f increases, 1+3f increases.
<span>From the message you sent me:
when you breathe normally, about 12 % of the air of your lungs is replaced with each breath. how much of the original 500 ml remains after 50 breaths
If you think of number of breaths that you take as a time measurement, you can model the amount of air from the first breath you take left in your lungs with the recursive function

Why does this work? Initially, you start with 500 mL of air that you breathe in, so

. After the second breath, you have 12% of the original air left in your lungs, or

. After the third breath, you have

, and so on.
You can find the amount of original air left in your lungs after

breaths by solving for

explicitly. This isn't too hard:

and so on. The pattern is such that you arrive at

and so the amount of air remaining after

breaths is

which is a very small number close to zero.</span>